HTML table 多继承形式，在茧中？

Question

我有一个 table 单元格。

Using cocoon how would I make a form in which each cell belongs_to the row, column, and table?

例如：

# Table
class Roster < ApplicationRecord
    has_many :timeslots, inverse_of: :roster
    has_many :games, inverse_of: :roster

    accepts_nested_attributes_for :timeslots, reject_if: :all_blank, allow_destroy: true
    accepts_nested_attributes_for :games, reject_if: :all_blank, allow_destroy: true
end

# Column
class Court < ApplicationRecord
  belongs_to :roster
  has_many :games

  accepts_nested_attributes_for :games, reject_if: :all_blank, allow_destroy: true
end

# Row
class Timeslot < ApplicationRecord
    belongs_to :roster
    has_many :games

    accepts_nested_attributes_for :games, reject_if: :all_blank, allow_destroy: true
end

# Cell
class Game < ApplicationRecord
    belongs_to :timeslot
    belongs_to :roster
end

我现在正在尝试为每场比赛的 :timeslot_id 和 :court_id 使用隐藏的 <input>，唯一的问题是您无法在保存时间段和场地之前获取 ID。我正在研究的另一个想法是让每个游戏都有一个隐藏的 <input> 它们所在的 row/column。

Answer 1

我终于明白了：每个单元格都有两个隐藏输入：

<%= cell.hidden_field :row %>
<%= cell.hidden_field :column %>

单元格 belongs_to 关联必须是可选的：

class Cell < ApplicationRecord
    belongs_to :table
    belongs_to :column, optional: true
    belongs_to :row, optional: true
end

并且 Table 有一个 after_save 回调：

after_save do |table|
    table.rows.each_with_index do |row,row_number|
        table.cells.each do |cell|
            if cell.row-1 == row_number
                cell.row = row
                cell.save()
            end
        end
    end
    table.columns.each_with_index do |column,column_number|
        table.cells.each do |cell|
            if cell.column-1 == column_number
                cell.column = column
                cell.save()
            end
        end
    end
end

可能有更好的方法来执行此操作，但我认为这是最简单的方法。您需要向数据库添加额外的两列：row 和 column（主要缺点）

HTML table 多继承形式，在茧中？

HTML table form with multiple inheritance, in cocoon?

forms

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multiple-inheritance

cocoon-gem