Java 在数组列表中打印姓氏

Question

我有这个

ArrayList<String> players = new ArrayList<String>();

players.add("Albert Pujols");
players.add("Jim Edmonds");
players.add("Josh Hamilton");
players.add("Mike Trout");
players.add("Adrian Gonzalez");
players.add("Price Fielder");
players.add("Steven Strasburg");
players.add("Jose Bautista");
players.add("Bryce Harper");
players.add("Mike Trout");

我如何创建一个只打印姓氏的方法：

Pujols
Edmonds
Hamilton
Trout
Gonzalez
Fielder
Strasburg
Bautista

我有类似的东西，但我卡住了：

public static void printLastName(ArrayList<String> players) {
    for (int i = 0; i < players.size(); i++)
        System.out.println(players.get(i));
}

Answer 1

我猜，所有名字都是单一的space separated.So，只是拆分并打印最后一部分

System.out.println(players.get(i).split(" ")[1]);

正如 Alexis C 提到的那样，您应该使用 firstName 和 lastName 创建一个模型 class 并将 class 实例存储在 List

中

Answer 2

您应该将代码更改为

public static void printLastName(ArrayList<String> players) {
for (int i = 0; i < players.size(); i++)
    System.out.println(players.get(i).split(" ")[1]);
}

Answer 3

你可以介绍一个 Player class.....

    public class Player {

        final String firstName;
        final String lastName;

        public Player(final String firstName, final String lastName) {
            this.firstName = firstName;
            this.lastName = lastName;
        }

        @Override
        public String toString() {
            return this.lastName;
        }

        @Override
        public boolean equals(final Object o) {
            if (this == o) {
                 return true;
            }
            if (!(o instanceof Player)) {
                return false;
            }

            final Player player = (Player) o;

            if (firstName != null ? !firstName.equals(player.firstName) : player.firstName != null) {
                return false;
            }
            return !(lastName != null ? !lastName.equals(player.lastName) : player.lastName != null);    
        }

        @Override
        public int hashCode() {
            int result = firstName != null ? firstName.hashCode() : 0;
            result = 31 * result + (lastName != null ? lastName.hashCode() : 0);
            return result;
        }     
    }

Answer 4

只需使用 \s 拆分 String 函数 split() 的 space 因为“ ”在 java

中不起作用

这是例子

 String lastname = players.get(i).Split("\s+")[1]; //even split("\s"); will also work

如果你想用 Pattern class 使用下面的代码

private static final Pattern SPACE = Pattern.compile(" ");//outside for loop
String lastname = SPACE.split(players.get(i))[1]; // inside for loop

Answer 5

你可能想让Arraylist持有一个String数组，比如

ArrayList<String[]> players = new ArrayList<String[]>();
String[] player1 = {"Albert", "Pujols"};
players.add(player1);
System.out.println(players.get(0)[1]);

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