使用更新的整数值格式化字符串以与文本框一起显示为列

Question

如果我的字符串更新后的整数值最多为 8 位：

 string Str = ("A1: [ " + int1 + " ] A2: [ " + int2  + " ]" +  
           "\r\nA3: [ " + int3 + " ] A4: [ " + int4  + " ]" +  
           "\r\nB1: [ " + int5 + " ] B2: [ " + int6  + " ]" + 
           "\r\nB3: [ " + int7 + " ] B4: [ " + int2  + " ]\r\n");

即：

  A1: [ 126.453 ] A2: [ 8.940 ]
  A3: [ 11.3 ] A4: [ 122.4 ]    
  B1: [ 6566.2 ] B2: [ 3444.76 ]    
  B3: [ 6.562 ] B4: [ 34.76 ]

如何将其格式化为迭代显示，文本框输出并排显示为列，各部分之间的间距与计数整数大小：

  A1: [ 126.453 ] A2: [ 348656.2 ]    B1: [ 35.7 ] B2: [ 65.1 ] 
  A3: [ 8.90 ] A4: [ 34.76 ]          B3: [ 3.97770 ] B4: [ 87700.67 ]

我找到了几种方法，但不太确定如何在这种情况下使用它，如何计算出更新后的数字并将我的字符串分配给整数长度：

    int pd = 3;
    int mx1 = "Hello World!".Length;
    int mx2 = "1234.56732".Length;
    int mx3 = "Name".Length;

    string f0 = "{0,-" + (mx1 + pd) + "}";
    string f1 = "{1,-" + (mx2 + pd) + "}";
    string f2 = "{2,-" + (mx3 + pd) + "}";

    string f = f0 + f1 + f2;

    Console.WriteLine(f, "Hello World!", 1234.56732, "Month");
    Console.WriteLine(f, "How are you?", 78.44, "Day");
    Console.WriteLine(f, "Hi", 2311.654, "Year");

很高兴听到一些有用的建议

Answer 1

您可以使用 String.PadRight() 方法对齐值：

var nums = new List<double>() {
    126.453, 8.94, 11.3, 122.4, 6566.2, 3444.76, 6.562, 34.76
};

var maxLen = nums.Select(n => n.ToString().Length).Max();
var strVals = nums.Select(n => n.ToString().PadRight(maxLen)).ToList();

textBox1.Font = new Font(FontFamily.GenericMonospace, 10);
var pos = 0;
foreach (var strVal in strVals)
    //Debug.Write($"NUM{++pos}: [ {strVal} ]    {(pos % 2 == 0 ? "\r\n" : "")}");
    textBox1.Text += $"NUM{++pos}: [ {strVal} ]    {(pos % 2 == 0 ? "\r\n" : "")}";

输出：

NUM1: [ 126,453 ]    NUM2: [ 8,94    ]    
NUM3: [ 11,3    ]    NUM4: [ 122,4   ]    
NUM5: [ 6566,2  ]    NUM6: [ 3444,76 ]    
NUM7: [ 6,562   ]    NUM8: [ 34,76   ]

使用更新的整数值格式化字符串以与文本框一起显示为列

Format string with updated integer values to display with textbox as columns

c#

string

textbox

string-formatting

winforms