我如何在 R 中 运行 一个带有季节性虚拟变量的指数 nls?

How do I run an exponential nls with seasonal dummies in R?

我在 运行 使用 R 中的季节性虚拟变量进行 nls 回归时遇到了问题。 我可以在没有季节性假人的情况下做到这一点,但不能。 这是我目前所拥有的:

year=floor(time(lsts))
> month=round(time(lsts)-year,4)
> month.f=factor(month)
> dummies=model.matrix(~month.f)
hotdogNLS<-nls(lsts~beta1/(1+exp(beta2+beta3*t)),start=list(beta1=2500,beta2=0.5,beta3=-0.5),trace=F)

summary(hotdogNLS)

Formula: lsts ~ beta1/(1 + exp(beta2 + beta3 * t))

Parameters:
        Estimate Std. Error t value Pr(>|t|)    
beta1  2.030e+03  5.874e+01   34.55   <2e-16 ***
beta2  1.146e+00  5.267e-02   21.76   <2e-16 ***
beta3 -1.116e-02  7.668e-04  -14.56   <2e-16 ***
---
Signif. codes:  0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1

Residual standard error: 192.3 on 333 degrees of freedom

Number of iterations to convergence: 8 
Achieved convergence tolerance: 2.054e-06

如何包含季节性虚拟变量? 谢谢!

我认为 nls 的假人不会像在 glm 中那样实现,因为 nls 的 "formula" 是一个真正的数学公式,不像对于 glm

您仍然可以指定是否必须为虚拟的每个 class 单独评估参数:

    data(cars)
    # define the dummy
    cars$dummy <- as.factor(LETTERS[1:5])
    # code as 0/1 the dummy with a column per dummy level
    cars$A<- as.numeric(cars$dummy=="A")
    cars$B<- as.numeric(cars$dummy=="B")
    cars$C<- as.numeric(cars$dummy=="C")
    cars$D<- as.numeric(cars$dummy=="D")
    cars$E<- as.numeric(cars$dummy=="E")

    # precise in the formula where the dummy level should play out
    # here in the intercept:
    model <- nls(dist~beta1*speed^beta2+beta3*A+beta4*B+beta5*C+beta6*D+beta7*E,data=cars)

    model

    Nonlinear regression model
      model: dist ~ beta1 * speed^beta2 + beta3 * A + beta4 * B + beta5 * C + beta6 * D + beta7 * E
      data: cars
      beta1   beta2   beta3   beta4   beta5   beta6   beta7 
      0.2069  1.8580  2.8266  5.3973 13.0002  9.3539  2.5361 
      residual sum-of-squares: 10040

      Number of iterations to convergence: 8 
      Achieved convergence tolerance: 4.924e-06

您可以使用 factor 对估计系数进行子集化,例如 alpha[dummy]

data(cars)
cars$dummy <- as.factor(LETTERS[1:5])

nls(dist ~ alpha[dummy] + beta1*speed^beta2, data=cars, start=list(beta1=.2, beta2=3, alpha=rep(10, nlevels(cars$dummy))))
#Nonlinear regression model
#  model: dist ~ alpha[dummy] + beta1 * speed^beta2
#   data: cars
#  beta1   beta2  alpha1  alpha2  alpha3  alpha4  alpha5 
# 0.2069  1.8580  2.8264  5.3971 13.0000  9.3537  2.5359 
# residual sum-of-squares: 10040
#
#Number of iterations to convergence: 12 
#Achieved convergence tolerance: 2.372e-06