id X 的 QBWebRTC 目前正忙? QB.webrtc.onRemoteStreamListener 没有开火。 Quickblox Javascript SDK + angular + WebRTC
QBWebRTC with id X is busy at the moment? QB.webrtc.onRemoteStreamListener is not firing. Quickblox Javascript SDK + angular + WebRTC
我按照文档看了三遍了,还是不能接电话。这是代码:
$scope.occupants = [6184, 6186];
$scope.session = QB.webrtc.createNewSession($scope.occupants, QB.webrtc.CallType.VIDEO);
$scope.localMediaParams = {
audio: true,
video: true,
options: {
muted: true,
mirror: true
},
elemId: 'localVideoEl',
optional: {
minWidth: 240,
maxWidth: 320,
minHeight: 160,
maxHeight: 240
}
};
$scope.startCall = function() {
if (angular.equals($scope.recipients, {})) {
alert('Please choose a person to call');
}else {
if (angular.equals($scope.session, {})) {
console.log('session hasn\'t been started');
$scope.session.stop({});
$scope.session = {};
return false;
}else {
$scope.session.getUserMedia($scope.localMediaParams, function(err, stream) {
if (err){
console.log(err);
}else{
console.log(stream);
$scope.session.call({}, function(error) {
console.log(error);
});
}
});
}
}
};
$scope.answerCall = function() {
$scope.session.getUserMedia($scope.localMediaParams, function(err, stream) {
if (err){
console.log(err);
$scope.session.stop({});
}else{
console.log(stream);
$scope.session.accept({});
}
});
};
QB.webrtc.onRemoteStreamListener = function(session, userID, remoteStream) {
// attach the remote stream to DOM element
console.log('onRemoteStreamListener');
console.log($scope.session);
$scope.session.attachMediaStream('remoteVideoEl', remoteStream);
};
我有两个 ID 为 6184 和 6186 的用户。我正在从用户 6186 发起呼叫,控制台显示如下:
[QBWebRTC]: RTCPeerConnection init. userID: 6186, sessionID: 7e7ea17c-a207-4af0-82e1-744fbcce830e, type: offer
telemed.js:432 null
quickblox.min.js:86149 [QBWebRTC]: getAndSetLocalSessionDescription success
quickblox.min.js:86149 [QBWebRTC]: _startDialingTimer, dialingTimeInterval: 5000
quickblox.min.js:86149 [QBWebRTC]: _dialingCallback, answerTimeInterval: 0
quickblox.min.js:86149 [QBWebRTC]: getAndSetLocalSessionDescription success
quickblox.min.js:86149 [QBWebRTC]: _startDialingTimer, dialingTimeInterval: 5000
quickblox.min.js:86149 [QBWebRTC]: _dialingCallback, answerTimeInterval: 0
quickblox.min.js:86149 [QBWebRTC]: onCall. UserID:6186. SessionID: 7e7ea17c-a207-4af0-82e1-744fbcce830e
quickblox.min.js:86149 [QBWebRTC]: onReject. UserID:6184. SessionID: 7e7ea17c-a207-4af0-82e1-744fbcce830e
quickblox.min.js:86149 [QBWebRTC]: _clearDialingTimer
quickblox.min.js:86149 [QBWebRTC]: All peer connections closed: false
quickblox.min.js:86149 [QBWebRTC]: onIceConnectionStateCallback: closed
quickblox.min.js:86149 [QBWebRTC]: _dialingCallback, answerTimeInterval: 5000
quickblox.min.js:86149 [QBWebRTC]: onCall. UserID:6186. SessionID: 7e7ea17c-a207-4af0-82e1-744fbcce830e
quickblox.min.js:86149 [QBWebRTC]: Stop, extension: {}
quickblox.min.js:86149 [QBWebRTC]: _close
quickblox.min.js:86149 [QBWebRTC]: _clearDialingTimer
quickblox.min.js:86149 [QBWebRTC]: onIceConnectionStateCallback: closed
现在在应答端,我看到正在生成一个呼叫,但随后它说发起呼叫者正忙:
[QBWebRTC]: onCall. UserID:6186. SessionID: 7e7ea17c-a207-4af0-82e1-744fbcce830e
quickblox.min.js:86149 [QBWebRTC]: User with id 6186 is busy at the moment.
quickblox.min.js:86149 [QBWebRTC]: onStop. UserID:6186. SessionID: 7e7ea17c-a207-4af0-82e1-744fbcce830e
谁能告诉我这是怎么回事,为什么 QB.webrtc.onRemoteStreamListener 没有在应答端触发?
还有一件事:
在我点击结束通话后,我收到了这个错误,我也不明白,因为它的英语也很糟糕:
[QBWebRTC]: onStop. UserID:6186. SessionID: 7e7ea17c-a207-4af0-82e1-744fbcce830e
quickblox.min.js:86161 [QBWebRTC]: Ignore 'onStop', there is no information about session 7e7ea17c-a207-4af0-82e1-744fbcce830e by some reason.
I am initiating the call from User 6186 and the console
您不必在占用者中列出您当前用户的 ID:
所以而不是
$scope.occupants = [6184, 6186];
你应该使用
$scope.occupants = [6184];
我无法接听电话的原因是我没有附加来自 QB.webrtc.onCallListener 侦听器的流。
QB.webrtc.onCallListener = function(session, extension) {
$scope.session = session;
console.log('User '+session.currentUserID+' is calling');
};
该文档未能解释占用者数组中需要包含哪些用户,以及当流到达该侦听器后您应该如何处理流。从 angular 的角度来看,如果您没有将 QB.webrtc.onCallListener 流附加到会话或 $scope.session 对象,您应该得到 $scope.session 或会话未定义。同样,正如 Igor 指出的那样,您不应将您的用户 ID 包含在 occupants 数组中。
我按照文档看了三遍了,还是不能接电话。这是代码:
$scope.occupants = [6184, 6186];
$scope.session = QB.webrtc.createNewSession($scope.occupants, QB.webrtc.CallType.VIDEO);
$scope.localMediaParams = {
audio: true,
video: true,
options: {
muted: true,
mirror: true
},
elemId: 'localVideoEl',
optional: {
minWidth: 240,
maxWidth: 320,
minHeight: 160,
maxHeight: 240
}
};
$scope.startCall = function() {
if (angular.equals($scope.recipients, {})) {
alert('Please choose a person to call');
}else {
if (angular.equals($scope.session, {})) {
console.log('session hasn\'t been started');
$scope.session.stop({});
$scope.session = {};
return false;
}else {
$scope.session.getUserMedia($scope.localMediaParams, function(err, stream) {
if (err){
console.log(err);
}else{
console.log(stream);
$scope.session.call({}, function(error) {
console.log(error);
});
}
});
}
}
};
$scope.answerCall = function() {
$scope.session.getUserMedia($scope.localMediaParams, function(err, stream) {
if (err){
console.log(err);
$scope.session.stop({});
}else{
console.log(stream);
$scope.session.accept({});
}
});
};
QB.webrtc.onRemoteStreamListener = function(session, userID, remoteStream) {
// attach the remote stream to DOM element
console.log('onRemoteStreamListener');
console.log($scope.session);
$scope.session.attachMediaStream('remoteVideoEl', remoteStream);
};
我有两个 ID 为 6184 和 6186 的用户。我正在从用户 6186 发起呼叫,控制台显示如下:
[QBWebRTC]: RTCPeerConnection init. userID: 6186, sessionID: 7e7ea17c-a207-4af0-82e1-744fbcce830e, type: offer
telemed.js:432 null
quickblox.min.js:86149 [QBWebRTC]: getAndSetLocalSessionDescription success
quickblox.min.js:86149 [QBWebRTC]: _startDialingTimer, dialingTimeInterval: 5000
quickblox.min.js:86149 [QBWebRTC]: _dialingCallback, answerTimeInterval: 0
quickblox.min.js:86149 [QBWebRTC]: getAndSetLocalSessionDescription success
quickblox.min.js:86149 [QBWebRTC]: _startDialingTimer, dialingTimeInterval: 5000
quickblox.min.js:86149 [QBWebRTC]: _dialingCallback, answerTimeInterval: 0
quickblox.min.js:86149 [QBWebRTC]: onCall. UserID:6186. SessionID: 7e7ea17c-a207-4af0-82e1-744fbcce830e
quickblox.min.js:86149 [QBWebRTC]: onReject. UserID:6184. SessionID: 7e7ea17c-a207-4af0-82e1-744fbcce830e
quickblox.min.js:86149 [QBWebRTC]: _clearDialingTimer
quickblox.min.js:86149 [QBWebRTC]: All peer connections closed: false
quickblox.min.js:86149 [QBWebRTC]: onIceConnectionStateCallback: closed
quickblox.min.js:86149 [QBWebRTC]: _dialingCallback, answerTimeInterval: 5000
quickblox.min.js:86149 [QBWebRTC]: onCall. UserID:6186. SessionID: 7e7ea17c-a207-4af0-82e1-744fbcce830e
quickblox.min.js:86149 [QBWebRTC]: Stop, extension: {}
quickblox.min.js:86149 [QBWebRTC]: _close
quickblox.min.js:86149 [QBWebRTC]: _clearDialingTimer
quickblox.min.js:86149 [QBWebRTC]: onIceConnectionStateCallback: closed
现在在应答端,我看到正在生成一个呼叫,但随后它说发起呼叫者正忙:
[QBWebRTC]: onCall. UserID:6186. SessionID: 7e7ea17c-a207-4af0-82e1-744fbcce830e
quickblox.min.js:86149 [QBWebRTC]: User with id 6186 is busy at the moment.
quickblox.min.js:86149 [QBWebRTC]: onStop. UserID:6186. SessionID: 7e7ea17c-a207-4af0-82e1-744fbcce830e
谁能告诉我这是怎么回事,为什么 QB.webrtc.onRemoteStreamListener 没有在应答端触发?
还有一件事:
在我点击结束通话后,我收到了这个错误,我也不明白,因为它的英语也很糟糕:
[QBWebRTC]: onStop. UserID:6186. SessionID: 7e7ea17c-a207-4af0-82e1-744fbcce830e
quickblox.min.js:86161 [QBWebRTC]: Ignore 'onStop', there is no information about session 7e7ea17c-a207-4af0-82e1-744fbcce830e by some reason.
I am initiating the call from User 6186 and the console
您不必在占用者中列出您当前用户的 ID:
所以而不是
$scope.occupants = [6184, 6186];
你应该使用
$scope.occupants = [6184];
我无法接听电话的原因是我没有附加来自 QB.webrtc.onCallListener 侦听器的流。
QB.webrtc.onCallListener = function(session, extension) {
$scope.session = session;
console.log('User '+session.currentUserID+' is calling');
};
该文档未能解释占用者数组中需要包含哪些用户,以及当流到达该侦听器后您应该如何处理流。从 angular 的角度来看,如果您没有将 QB.webrtc.onCallListener 流附加到会话或 $scope.session 对象,您应该得到 $scope.session 或会话未定义。同样,正如 Igor 指出的那样,您不应将您的用户 ID 包含在 occupants 数组中。