TypeError: cannot convert dictionary update sequence element #0 to a sequence - Odoo v10 community migration

TypeError: cannot convert dictionary update sequence element #0 to a sequence - Odoo v10 community migration

我的模块从 Odoov8 迁移到 Ovoo10 社区时仍然存在一些错误

我有这个方法:

@api.model
def search_partner_seniat(self):
    """ Check vat of the partner and update iva rate
    """
    self.ensure_one()
    vat = self.vat.upper()
    res = {
        'name': _('The requested contributor does not exist'),
        'vat_subjected': False,
        'vat': vat,
        'wh_iva_agent': False,
        'wh_iva_rate': 0.0
    }

    if 'VE' in vat:
        vat = vat[2:]

    # assumption: both methods in new api style
    if self.env['res.partner'].check_vat_ve(vat):  # check_vat_ve() should be @api.model
        res = self.env['seniat.url']._dom_giver(vat)  # _dom_giver() should be @api.model
    self.write(res)

    return {
        'type': 'ir.actions.act_window',
        'res_model': 'search.info.partner.seniat',
        'view_mode': 'form',
        'view_type': 'form',
        'res_id': self.id,
        'views': [(False, 'form')],
        'target': 'new',
    }

我知道这是一个按钮,它应该(或者至少看起来)是 @api.multi,但是之前,当它是 @api.multi 时,Odoo 告诉我这个方法应该是 api.model 所以我改变了它。

我不知道,但现在,每次我点击它,它都会说:

Traceback (most recent call last):
File "/home/kristian/.virtualenvs/odoov10/lib/python2.7/site-packages/odoo-10.0rc1c_20161005-py2.7.egg/odoo/http.py", line 638, in _handle_exception
return super(JsonRequest, self)._handle_exception(exception)
File "/home/kristian/.virtualenvs/odoov10/lib/python2.7/site-packages/odoo-10.0rc1c_20161005-py2.7.egg/odoo/http.py", line 675, in dispatch
result = self._call_function(**self.params)
File "/home/kristian/.virtualenvs/odoov10/lib/python2.7/site-packages/odoo-10.0rc1c_20161005-py2.7.egg/odoo/http.py", line 331, in _call_function
return checked_call(self.db, *args, **kwargs)
File "/home/kristian/.virtualenvs/odoov10/lib/python2.7/site-packages/odoo-10.0rc1c_20161005-py2.7.egg/odoo/service/model.py", line 119, in wrapper
return f(dbname, *args, **kwargs)
File "/home/kristian/.virtualenvs/odoov10/lib/python2.7/site-packages/odoo-10.0rc1c_20161005-py2.7.egg/odoo/http.py", line 324, in checked_call
result = self.endpoint(*a, **kw)
File "/home/kristian/.virtualenvs/odoov10/lib/python2.7/site-packages/odoo-10.0rc1c_20161005-py2.7.egg/odoo/http.py", line 933, in __call__
return self.method(*args, **kw)
File "/home/kristian/.virtualenvs/odoov10/lib/python2.7/site-packages/odoo-10.0rc1c_20161005-py2.7.egg/odoo/http.py", line 504, in response_wrap
response = f(*args, **kw)
File "/home/kristian/odoov10/odoo-10.0rc1c-20161005/odoo/addons/web/controllers/main.py", line 866, in call_button
action = self._call_kw(model, method, args, {})
File "/home/kristian/odoov10/odoo-10.0rc1c-20161005/odoo/addons/web/controllers/main.py", line 854, in _call_kw
return call_kw(request.env[model], method, args, kwargs)
File "/home/kristian/.virtualenvs/odoov10/lib/python2.7/site-packages/odoo-10.0rc1c_20161005-py2.7.egg/odoo/api.py", line 679, in call_kw
return call_kw_model(method, model, args, kwargs)
File "/home/kristian/.virtualenvs/odoov10/lib/python2.7/site-packages/odoo-10.0rc1c_20161005-py2.7.egg/odoo/api.py", line 662, in call_kw_model
recs = self.with_context(context or {})
File "/home/kristian/.virtualenvs/odoov10/lib/python2.7/site-packages/odoo-10.0rc1c_20161005-py2.7.egg/odoo/models.py", line 4850, in with_context
context = dict(args[0] if args else self._context, **kwargs)
TypeError: cannot convert dictionary update sequence element #0 to a sequence

有没有人能解释一下这个?

如果你想 return 来自 Buttons 方法的字典,那么你必须需要使它 @api.multi.

@api.multi
def search_partner_seniat(self):
    # do stuff
    return dict

这可能对您有所帮助。 谢谢

使用@api.multi 而不是模型,并且您正在尝试用 null 写入记录 self.write(res),而 @api.model 仅在您没有 id 的情况下使用关联当前记录。例如:在 Odoo 上创建方法

所以在这里我建议将代码更改为:使用 如果 len(res): self.write(分辨率)