条件求和 (Alasql)

Question

我最近发现了 Alasql，它已经为我节省了大量的数据操作工作。

现在我正在尝试汇总每个客户的年收入。我试过分区但没有成功，我试过这种条件方法，但它只有 returns 2013 年或 2014 年的数据，而不是同时：

    var custTable = alasql('SELECT CUSTOMER as customer, 
SUM(REVENUE::NUMBER) AS revenueTotal, SUM(CASE WHEN YEAR = "2013" THEN 
REVENUE::NUMBER END) AS revenue2013,  SUM(CASE WHEN YEAR = "2014" THEN 
REVENUE::NUMBER END) AS revenue2014   FROM ? GROUP BY CUSTOMER', 
[revenueTestData]);

基本上我想从中得到：

{"YEAR":"2013","MONTH":"1","CUSTOMER":"Some Customer","REVENUE":"7533.36"}, {"YEAR":"2014","MONTH":"1","CUSTOMER":"Some Customer","REVENUE":"10000"}

为此：

{"CUSTOMER":"Some Customer","revenueTotal":"17533.36","revenue2013":7533.36","revenue2014":"10000"}

为什么只查询 return 2013 OR 2014，而不是两者？条件求和的正确方法是什么？

（顺便说一句，我无法为 ALASQL 创建新标签，但我认为在不久的将来它会对某些人派上用场 - 有人可以创建它吗？）

Answer 1

试试这个：

SUM(CASE WHEN YEAR = "2013" THEN REVENUE::NUMBER ELSE 0 END) AS revenue2013,  
SUM(CASE WHEN YEAR = "2014" THEN REVENUE::NUMBER ELSE 0 END) AS revenue2014

条件求和 (Alasql)

Conditional summing (Alasql)

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querying

data-manipulation

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alasql