Preg_match 匹配开始和结束之间的单词

Question

我讨厌 preg_match 语法！

[file.txt] 来源：

  sth = s("Would you like to go to the cinema "+
                               "With me?");
        }
        else if (something)
        {
            sth = s("Would you like to go to the cinema "+
                               "With me?");
        } else {
sth = s("Sure, no problem");
}

PHP:

$file = file_get_contents("file.txt");
$file = str_replace(PHP_EOL, '', $file);
preg_match_all("/s\(\"(.*) /", $file, $matches);
var_dump($matches);

这显示了太多的单词，因为我有 "start point" 并且没有模式结束。但我不知道，如何创建带有这样的结尾分隔符的 preg：

preg_match("/ [s(" .... ")] /")

我想从源中提取：

"Would you like to go to the cinema With me?" 
"Would you like to go to the cinema With me?" 
"Sure, no problem"

请帮我创建模式。

Answer 1

你可以试试这个，

$regex = "/s$\\"(.*?)\\"$;/s";

并从输出

中替换+和"

Demo

Preg_match 匹配开始和结束之间的单词

Preg_match match words between start and end

php

preg-match