如何将这 25 个 INSERT 查询合并为一个查询？

Question

我有一个基于网络的系统，它读取 excel 文件的 sheet（每个上传的 sheet 是 6 行 5 列），如下所示：

下面是我正在使用的代码（出于演示目的，我为 $entry 设置了静态值，但它的实际代码是例如 $entry1=$objTpl->getActiveSheet()->getCell('A2')->getValue();

$con=mysqli_connect("localhost","root","","view");

if(isset($_POST['submit']))
{
$entry1 = 1;
$entry2 = 2;
$entry3 = 3;
$entry4 = 4;
$entry5 = 5;
$entry6 = 1;
$entry7 = 2;
$entry8 = 0;
$entry9 = 4;
$entry10 = 0;
$entry11 = 0;
$entry12 = 2;
$entry13 = 3;
$entry14 = 4;
$entry15 = 0;
$entry16 = 1;
$entry17 = 2;
$entry18 = 0;
$entry19 = 0;
$entry20 = 5;
$entry21 = 1;
$entry22 = 0;
$entry23 = 3;
$entry24 = 0;
$entry25 = 5;

if($entry1 != 0 || !empty($entry1))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry1','$entry1')");
}
if($entry2 != 0 || !empty($entry2))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry2','$entry2')");
}
if($entry3 != 0 || !empty($entry3))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry3','$entry3')");
}
if($entry4 != 0 || !empty($entry4))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry4','$entry4')");
}
if($entry5 != 0 || !empty($entry5))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry5','$entry5')");
}
if($entry6 != 0 || !empty($entry6))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry6','$entry6')");
}
if($entry7 != 0 || !empty($entry7))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry7','$entry7')");
}
if($entry8 != 0 || !empty($entry8))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry8','$entry8')");
}
if($entry9 != 0 || !empty($entry9))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry9','$entry9')");
}
if($entry10 != 0 || !empty($entry10))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry10','$entry10')");
}
if($entry11 != 0 || !empty($entry11))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry11','$entry11')");
}
if($entry12 != 0 || !empty($entry12))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry12','$entry12')");
}
if($entry13 != 0 || !empty($entry13))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry13','$entry13')");
}
if($entry14 != 0 || !empty($entry14))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry14','$entry14')");
}
if($entry15 != 0 || !empty($entry15))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry15','$entry15')");
}
if($entry16 != 0 || !empty($entry16))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry16','$entry16')");
}
if($entry17 != 0 || !empty($entry17))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry17','$entry17')");
}
if($entry18 != 0 || !empty($entry18))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry18','$entry18')");
}
if($entry19 != 0 || !empty($entry19))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry19','$entry19')");
}
if($entry20 != 0 || !empty($entry20))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry20','$entry20')");
}
if($entry21 != 0 || !empty($entry21))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry21','$entry21')");
}
if($entry22 != 0 || !empty($entry22))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry22','$entry22')");
}
if($entry23 != 0 || !empty($entry23))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry23','$entry23')");
}
if($entry24 != 0 || !empty($entry24))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry24','$entry24')");
}
if($entry25 != 0 || !empty($entry25))
{   
mysqli_query($con,"INSERT INTO viewer(base_id,name,value) VALUES('1','entry25','$entry25')");
}
}
?>

我有几个问题：

是否可以将所有这些语句合二为一？
执行一个大查询而不是多个大查询时，性能是否有任何显着变化？

Answer 1

是的，您可以使用一条 SQL 语句来完成此操作。它会像这样工作。您可以根据需要将任意多组 (val, val, val) 串在一起。（整个查询的字符串长度是有限制的，但是在MySQL中已经很大了）。

INSERT INTO viewer(base_id,name,value) VALUES
      ('1','entry1','$entry1'),
      ('1','entry2','$entry2'),
      ('1','entry3','$entry3')

如果您将内容插入到 InnoDB table，当您的连接处于自动提交模式时，您可以通过执行此操作获得相当多的性能提升。那是因为你将插入中的所有行一起提交，并且提交有开销。

编辑在 php 中，如果您有一个数组 $values，其中的每个元素都包含一个文本字符串，例如 (1,'val','val')，您可以使用此代码来创建查询字符串。

$sqlstart = 'INSERT INTO viewer(base_id,name,value) VALUES ';
$sql = sqlstart . implode(',' , $values);

这会在之间放置逗号，但不在 $values 数组的元素之后。 implode() is made for this kind of purpose。

因此，您的代码可能如下所示：

$values = array();  /* make an empty array */
if ($entry1 != 0 || !empty($entry1)) {
   $values[] = "('1','entry1','$entry1')";  /* append to array */
}
if ($entry2 != 0 || !empty($entry2)) {
   $values[] = "('1','entry2','$entry2')";
}
/* etc etc for the rest of your $entry values */
$sqlstart = 'INSERT INTO viewer(base_id,name,value) VALUES ';
$sql = sqlstart . implode(',' , $values);

（请注意 SQL 插入漏洞）。

如何将这 25 个 INSERT 查询合并为一个查询？

How can I join these 25 INSERT queries into just one?

php

mysql

transactions

sql-insert

sql-optimization