ProtoBuf 的 Golang 解析

Golang Parsing of ProtoBuf

我是 Golang 的新手,我正在尝试使用 Micro 框架和 Protobuf 框架在 Golang 中编写一个家庭自动化框架。

我目前很难尝试实现一个简单的注册表类型服务。

我遇到的问题的一个例子是我有以下问题,我希望能够获得设备列表,前提是客户端向 http://localhost:8080/view/devices

发出 GET 请求

我有以下 protobuf 定义:

syntax = "proto3";

service DRegistry {
    rpc View(ViewRequest) returns (DeviceRegistry) {}
} 

message DeviceRegistry {
    repeated Device devices = 1;
}

message ViewRequest {
    string Alias = 1;
}

message Device {
    string Alias = 1;
    string HWAddress = 2;
    string WakeUpMethod = 3;
    repeated string BoundServices = 4;
}

然后在我的服务定义中有以下内容:

package main

import (
    "log"

    micro "github.com/micro/go-micro"
    proto "github.com/srizzling/gotham/proto/device"

    "golang.org/x/net/context"
)

// DRegistry stands for Device Registry and is how devices register to Gotham.
type DRegistry struct{}

var devices map[string]proto.Device

func (g *DRegistry) View(ctx context.Context, req *proto.ViewRequest, rsp *proto.DeviceRegistry) error {
    filter := req.Alias
devices, err := filterDevices(filter)
rsp.Devices = devices
}

func filterDevices(filter string) (*[]proto.Device, error) {
    // Currently only supports listing a single service for now
    // TODO: expand filter to be more consise
    filteredDevices := make([]proto.Device, 0, len(devices))
    for _, e := range devices {
        for _, f := range e.BoundServices {
            if f == filter {
                filteredDevices = append(filteredDevices, e)
            }
        }
    }
    return &filteredDevices, nil
}

func main() {
    service := micro.NewService(
        micro.Name("DRegistry"),
    )
    proto.RegisterDRegistryHandler(service.Server(), new(DRegistry))

    if err := service.Run(); err != nil {
        log.Fatal(err)
    }
}

我遇到的问题是我的 IDE(Visual Studio 代码)符合我 cannot use devices (type *[]device.Device) as type []*device.Device in assignment 的要求,这令人困惑。

TLDR:如何将 proto.Devices 的集合分配给 proto.DeviceRegistry?

func filterDevices(filter string) ([]*proto.Device, error) {
    // Currently only supports listing a single service for now
    // TODO: expand filter to be more consise
    filteredDevices := make([]*proto.Device, 0, len(devices))
    for _, e := range devices {
        for _, f := range e.BoundServices {
            if f == filter {
                filteredDevices = append(filteredDevices, &e)
            }
        }
    }
    return filteredDevices, nil
}

指针切片 ([]*) 和指向切片的指针 (*[]) 之间存在 的区别。您正在 returning 一个指向切片的指针,而您想要的是一个指针切片。我们可以通过以下方式解决这个问题:

  • 正在将您的 filterDevices 签名更新为 return 一片指针
  • 正在更新您的 make 调用以生成指针片段
  • 在追加调用中获取 e 的地址(我们需要一部分指向设备的指针)
  • 不是 returning slice的地址