如何测试 Connexion/Flask 应用程序？

Question

我正在使用 Connexion framework for Flask 构建微服务。我想使用 py.test.

为我的应用程序编写测试

在 pytest-flask 文档中，它说要在 conftest.py 中创建一个固定装置，它会像这样创建应用程序：

`conftest.py`

import pytest

from api.main import create_app


@pytest.fixture
def app():
    app = create_app()
    return app

在我的测试中，我使用这样的 client 夹具：

`test_api.py`

def test_api_ping(client):
    res = client.get('/status')
    assert res.status == 200

然而，当我运行 py.test 时，我收到以下错误消息：

==================================== ERRORS ====================================
_______________________ ERROR at setup of test_api_ping ________________________

request = <SubRequest '_monkeypatch_response_class' for <Function 'test_api_ping'>>
monkeypatch = <_pytest.monkeypatch.MonkeyPatch instance at 0x7f9f76b76518>

    @pytest.fixture(autouse=True)
    def _monkeypatch_response_class(request, monkeypatch):
        """Set custom response class before test suite and restore the original
        after. Custom response has `json` property to easily test JSON responses::
    
            @app.route('/ping')
            def ping():
                return jsonify(ping='pong')
    
            def test_json(client):
                res = client.get(url_for('ping'))
                assert res.json == {'ping': 'pong'}
    
        """
        if 'app' not in request.fixturenames:
            return
    
        app = request.getfuncargvalue('app')
        monkeypatch.setattr(app, 'response_class',
>                           _make_test_response_class(app.response_class))
E       AttributeError: 'App' object has no attribute 'response_class'

如何让 py.test 工作？这是我的 create_app 函数：

`main.py`

import connexion


def create_app():
    app = connexion.App(__name__, port=8002,)
    app.add_api('swagger.yaml')
    return app


if __name__ == "__main__":
    create_app().run()

Answer 1

使用灯具

test_api.py

import pytest
import connexion

flask_app = connexion.FlaskApp(__name__)
flask_app.add_api('swagger.yml')


@pytest.fixture(scope='module')
def client():
    with flask_app.app.test_client() as c:
        yield c


def test_health(client):
    response = client.get('/health')
    assert response.status_code == 200

swagger.yml

swagger: '2.0'
info:
  title: My API
  version: '1.0'
consumes:
  - application/json
produces:
  - application/json
schemes:
  - https
paths:
  /health:
    get:
      tags: [Health]
      operationId: api.health
      summary: Health Check
      responses:
        '200':
          description: Status message from server describing current health

api.py

def health():
    return {'msg': 'ok'}, 200

使用 Swagger 测试器

另一种使用swagger-tester的解决方案：

test_api.py

from swagger_tester import swagger_test

authorize_error = {
    'get': {
        '/health': [200],
    }
}

def test_swagger():
    swagger_test('swagger.yml', authorize_error=authorize_error)

这个库很酷的一点是您可以使用规范中提供的示例。但我不认为它与 connexion.RestyResolver 开箱即用：您必须在每个端点指定 OperationId。

Answer 2

import pytest
from json import JSONEncoder
import pytest
from connexion import App

SWAGGER_PATH = "path_to_directory_that_containes_swagger_file"

@pytest.fixture
def app():
    app = App(__name__, specification_dir=SWAGGER_PATH)
    app.app.json_encoder = JSONEncoder
    app.add_api("swagger.yaml")
    app_client = app.app.test_client()
    return app_client


def test_health(app) -> None:
    """
    :except: success
    """
    response = app.get("/health", content_type='application/json')
    assert response.status_code == 200

有关更多信息，请查看 this。

如何测试 Connexion/Flask 应用程序？

How to test a Connexion/Flask app?

python

pytest

flask

swagger

connexion

`conftest.py`

`test_api.py`

`main.py`

使用灯具

使用 Swagger 测试器