在 AFHTTPRequestOperation 失败时显示 UIAlertView
Display UIAlertView on AFHTTPRequestOperation failure
当 JSON 响应在用户登录时出现错误时,我试图在 AFHTTPRequestOperation 的失败块中显示 UIAlertView。我不确定为什么我的代码不是工作,但我是 AFNetworking 的新手。
出于某种原因,成功的 UIAlertView 即使在出错时也会显示。即使我没有在登录的 UITextFields 中输入任何内容。如何让失败或错误块中的 UIAlertView 显示出来?
JSON 对错误的响应是:
JSON: {
code = Error;
message = "Incorrect Username or Password!";
}
成功后 JSON 响应为:
JSON: {
code = Success;
message = "Login Successful!";
}
登录视图控制器:
@interface LoginSectionViewController ()
@property (strong, nonatomic) IBOutlet UIButton *loginButton;
@property (strong, nonatomic) IBOutlet UITextField *usernameTextField;
@property (strong, nonatomic) IBOutlet UITextField *passwordTextField;
@end
- (IBAction)loginAction:(id)sender {
AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
NSDictionary *parameters = @{@"username": self.usernameTextField.text, @"password": self.passwordTextField.text};
[manager POST:@"http://api.mysite.com/login.php" parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSLog(@"JSON: %@", responseObject);
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Success"
message:@"Login Successful!"
delegate:self
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alert show];
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
UIAlertView *alertError = [[UIAlertView alloc] initWithTitle:@"Error"
message:@"Incorrect Username or Password!"
delegate:self
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alertError show];
}];
}
- (void)alertView:(UIAlertView *)alertView didDismissWithButtonIndex:(NSInteger)buttonIndex {
if (buttonIndex == 0) {
[self.navigationController popToRootViewControllerAnimated:YES];
}
}
success
和 failure
块用于指示请求中的基本错误(例如请求失败,因为没有互联网连接,响应不是 JSON 并且失败解析等)。但它并没有查看 JSON 内容本身。
这取决于你。在您的 success
块(即 "successfully received JSON response")中,您可以检查 JSON 的内容以向用户指示登录是否成功。
我还没有测试过这个,但希望这能说明这个想法:
[manager POST:@"http://api.mysite.com/login.php" parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSLog(@"JSON: %@", responseObject);
NSDictionary *responseDictionary = responseObject;
if ([responseDictionary[@"code"] isEqualToString:@"Success"]) {
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Success"
message:@"Login Successful!"
delegate:self
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alert show];
} else {
UIAlertView *alertError = [[UIAlertView alloc] initWithTitle:@"Login failed"
message:responseDictionary[@"message"]
delegate:self
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alertError show];
}
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
UIAlertView *alertError = [[UIAlertView alloc] initWithTitle:@"Network problem"
message:[error localizedDescription]
delegate:self
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alertError show];
}];
当 JSON 响应在用户登录时出现错误时,我试图在 AFHTTPRequestOperation 的失败块中显示 UIAlertView。我不确定为什么我的代码不是工作,但我是 AFNetworking 的新手。
出于某种原因,成功的 UIAlertView 即使在出错时也会显示。即使我没有在登录的 UITextFields 中输入任何内容。如何让失败或错误块中的 UIAlertView 显示出来?
JSON 对错误的响应是:
JSON: {
code = Error;
message = "Incorrect Username or Password!";
}
成功后 JSON 响应为:
JSON: {
code = Success;
message = "Login Successful!";
}
登录视图控制器:
@interface LoginSectionViewController ()
@property (strong, nonatomic) IBOutlet UIButton *loginButton;
@property (strong, nonatomic) IBOutlet UITextField *usernameTextField;
@property (strong, nonatomic) IBOutlet UITextField *passwordTextField;
@end
- (IBAction)loginAction:(id)sender {
AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
NSDictionary *parameters = @{@"username": self.usernameTextField.text, @"password": self.passwordTextField.text};
[manager POST:@"http://api.mysite.com/login.php" parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSLog(@"JSON: %@", responseObject);
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Success"
message:@"Login Successful!"
delegate:self
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alert show];
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
UIAlertView *alertError = [[UIAlertView alloc] initWithTitle:@"Error"
message:@"Incorrect Username or Password!"
delegate:self
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alertError show];
}];
}
- (void)alertView:(UIAlertView *)alertView didDismissWithButtonIndex:(NSInteger)buttonIndex {
if (buttonIndex == 0) {
[self.navigationController popToRootViewControllerAnimated:YES];
}
}
success
和 failure
块用于指示请求中的基本错误(例如请求失败,因为没有互联网连接,响应不是 JSON 并且失败解析等)。但它并没有查看 JSON 内容本身。
这取决于你。在您的 success
块(即 "successfully received JSON response")中,您可以检查 JSON 的内容以向用户指示登录是否成功。
我还没有测试过这个,但希望这能说明这个想法:
[manager POST:@"http://api.mysite.com/login.php" parameters:parameters success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSLog(@"JSON: %@", responseObject);
NSDictionary *responseDictionary = responseObject;
if ([responseDictionary[@"code"] isEqualToString:@"Success"]) {
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Success"
message:@"Login Successful!"
delegate:self
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alert show];
} else {
UIAlertView *alertError = [[UIAlertView alloc] initWithTitle:@"Login failed"
message:responseDictionary[@"message"]
delegate:self
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alertError show];
}
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
UIAlertView *alertError = [[UIAlertView alloc] initWithTitle:@"Network problem"
message:[error localizedDescription]
delegate:self
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alertError show];
}];