如何将任何 pascal case JSON 对象转换为 camel case JSON 对象?
How to convert any pascal case JSON object to camel case JSON object?
我尝试使用 CamelCasePropertyNamesContractResolver,但它无法将 Pascal 属性 名称转换为驼峰式大小写?
注意:这只是一个示例,我的 json 输入未知,我只有 json pascal 大小写。
using Newtonsoft.Json;
using Newtonsoft.Json.Serialization;
using System;
namespace Example
{
class Program
{
static void Main(string[] args)
{
object myJsonInput = @"{'Id':'123','Name':'abc'}"; //Example only, any json.
object myJsonOutput;
var jsonSerializersettings = new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
myJsonOutput = JsonConvert.DeserializeObject<object>(myJsonInput.ToString(),jsonSerializersettings);
//{{"Id": "123","Name": "abc"}}
}
}
}
Humanizer有Pascalize、Camelize等函数。你可以使用它或者只看他们的源代码。
/// <summary>
/// By default, pascalize converts strings to UpperCamelCase also removing underscores
/// </summary>
/// <param name="input"></param>
/// <returns></returns>
public static string Pascalize(this string input)
{
return Regex.Replace(input, "(?:^|_)(.)", match => match.Groups[1].Value.ToUpper());
}
/// <summary>
/// Same as Pascalize except that the first character is lower case
/// </summary>
/// <param name="input"></param>
/// <returns></returns>
public static string Camelize(this string input)
{
var word = Pascalize(input);
return word.Substring(0, 1).ToLower() + word.Substring(1);
}
结果如下:
"some_title".Pascalize() => "SomeTitle"
"some_title".Camelize() => "someTitle"
你的例子是序列化一个字符串。如果将输入转换为对象然后反序列化,它将起作用:
static void Main(string[] args)
{
var myJsonInput = @"{'Id':'123','Name':'abc'}";
var jsonSerializerSettings = new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
var interimObject = JsonConvert.DeserializeObject<ExpandoObject>(myJsonInput);
var myJsonOutput = JsonConvert.SerializeObject(interimObject, jsonSerializerSettings);
Console.Write(myJsonOutput);
Console.ReadKey();
}
我尝试使用 CamelCasePropertyNamesContractResolver,但它无法将 Pascal 属性 名称转换为驼峰式大小写?
注意:这只是一个示例,我的 json 输入未知,我只有 json pascal 大小写。
using Newtonsoft.Json;
using Newtonsoft.Json.Serialization;
using System;
namespace Example
{
class Program
{
static void Main(string[] args)
{
object myJsonInput = @"{'Id':'123','Name':'abc'}"; //Example only, any json.
object myJsonOutput;
var jsonSerializersettings = new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
myJsonOutput = JsonConvert.DeserializeObject<object>(myJsonInput.ToString(),jsonSerializersettings);
//{{"Id": "123","Name": "abc"}}
}
}
}
Humanizer有Pascalize、Camelize等函数。你可以使用它或者只看他们的源代码。
/// <summary>
/// By default, pascalize converts strings to UpperCamelCase also removing underscores
/// </summary>
/// <param name="input"></param>
/// <returns></returns>
public static string Pascalize(this string input)
{
return Regex.Replace(input, "(?:^|_)(.)", match => match.Groups[1].Value.ToUpper());
}
/// <summary>
/// Same as Pascalize except that the first character is lower case
/// </summary>
/// <param name="input"></param>
/// <returns></returns>
public static string Camelize(this string input)
{
var word = Pascalize(input);
return word.Substring(0, 1).ToLower() + word.Substring(1);
}
结果如下:
"some_title".Pascalize() => "SomeTitle"
"some_title".Camelize() => "someTitle"
你的例子是序列化一个字符串。如果将输入转换为对象然后反序列化,它将起作用:
static void Main(string[] args)
{
var myJsonInput = @"{'Id':'123','Name':'abc'}";
var jsonSerializerSettings = new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
var interimObject = JsonConvert.DeserializeObject<ExpandoObject>(myJsonInput);
var myJsonOutput = JsonConvert.SerializeObject(interimObject, jsonSerializerSettings);
Console.Write(myJsonOutput);
Console.ReadKey();
}