PHP 如何预匹配这个字符串？

Question

我有一长串 IP 地址和端口。我正在尝试从类似于此的列表中预匹配端口号：

/connect=;;41.26.162.36;;192.168.0.100;;8081;;
/connect=;;98.250.16.76;;192.168.0.24;;8080;;
/connect=;;216.152.60.12;;192.168.1.103;;8090;;
/connect=;;91.11.65.110;;192.168.1.3;;8081;;

我在使用以下方法匹配全球 IP 地址时没有遇到任何问题：

preg_match_all('/connect=;;(.+?);;/', $long, $ip);
            $ip = $ip[1][0];
            print_r($ip);

这对我来说非常有用，但我不知道如何预匹配位于行尾的端口。

Answer 1

试试这个方法...

    $re = "/connect=;;(.+?);;(\d{4});;/";
    $str = "/connect=;;41.26.162.36;;192.168.0.100;;8081;;/connect=;;98.250.16.76;;
    192.168.0.24;;8080;;/connect=;;216.152.60.12;;192.168.1.103;;8090;;/connect=;;
    91.11.65.110;;192.168.1.3;;8081;;";

    preg_match_all($re, $str, $matches);

解释：

  /connect=;;(.+?);;(\d{4});;/g

   connect=;; matches the characters connect=;; literally (case sensitive)
  1st Capturing group (.+?)
    .+? matches any character (except newline)
        Quantifier: +? Between one and unlimited times, as few times as possible, 
   expanding as needed [lazy]
   ;; matches the characters ;; literally
  2nd Capturing group (\d{4})
    \d{4} match a digit [0-9]
        Quantifier: {4} Exactly 4 times
  ;; matches the characters ;; literally
  g modifier: global. All matches (don't return on first match)

Answer 2

稍微扩展一下上面的答案：

if (preg_match_all('/connect=;;([\d\.]+);;([\d\.]+);;(\d+);;/',
                   $long, $matches, PREG_SET_ORDER)) {
  foreach($matches as $match) {
    list(,$ip1, $ip2, $port) = $match;
    /* Do stuff */
    echo "{$ip1} => {$ip2}:{$port}\n";
  }
}

您可以在 IP 检测上更聪明一些，但如果您的样本格式正确，这应该绰绰有余。

http://3v4l.org/FpGFD

Answer 3

由于您的日志将被严格可靠地格式化，您可以只扫描格式化的字符串。

https://www.php.net/manual/en/function.sscanf.php

sscanf() 不会像 preg_match_all() 那样产生不需要的全字符串匹配。

代码：(Demo)

$logs = <<<LOGS
/connect=;;41.26.162.36;;192.168.0.100;;8081;;
/connect=;;98.250.16.76;;192.168.0.24;;8080;;
/connect=;;216.152.60.12;;192.168.1.103;;8090;;
/connect=;;91.11.65.110;;192.168.1.3;;8081;;
LOGS;

foreach(explode(PHP_EOL, $logs) as $line) {
    sscanf($line, "/connect=;;%[^;];;%[^;];;%d;;", $ip1, $ip2, $port);
    var_export(
        [$ip1, $ip2, $port]
    );
    echo "\n";
}

输出：

array (
  0 => '41.26.162.36',
  1 => '192.168.0.100',
  2 => 8081,
)
array (
  0 => '98.250.16.76',
  1 => '192.168.0.24',
  2 => 8080,
)
array (
  0 => '216.152.60.12',
  1 => '192.168.1.103',
  2 => 8090,
)
array (
  0 => '91.11.65.110',
  1 => '192.168.1.3',
  2 => 8081,
)

PHP 如何预匹配这个字符串？

PHP How to preg match this string?

php

regex

preg-match