倒计时到 Python 中的目标日期时间
Count down to a target datetime in Python
我正在尝试创建一个程序,它需要一个目标时间(比如今天 16:00)并倒计时,每秒打印如下:
...
5
4
3
2
1
Time reached
我该怎么做?
您也可以使用 python threading
模块来执行此操作,如下所示:
from datetime import datetime
import threading
selected_date = datetime(2017,3,25,1,30)
def countdown() :
t = threading.Timer(1.0, countdown).start()
diff = (selected_date - datetime.now())
print diff.seconds
if diff.total_seconds() <= 1 : # To run it once a day
t.cancel()
countdown()
要在倒计时结束时打印 "Click Now",您可以这样做:
from datetime import datetime
import threading
selected_date = datetime(2017,3,25,4,4)
def countdown() :
t = threading.Timer(1.0, countdown)
t.start()
diff = (selected_date - datetime.now())
if diff.total_seconds() <= 1 : # To run it once a day
t.cancel()
print "Click Now"
else :
print diff.seconds
countdown()
这将导致这样的结果 每秒 :
2396
2395
2394
2393
...
我正在尝试创建一个程序,它需要一个目标时间(比如今天 16:00)并倒计时,每秒打印如下:
...
5
4
3
2
1
Time reached
我该怎么做?
您也可以使用 python threading
模块来执行此操作,如下所示:
from datetime import datetime
import threading
selected_date = datetime(2017,3,25,1,30)
def countdown() :
t = threading.Timer(1.0, countdown).start()
diff = (selected_date - datetime.now())
print diff.seconds
if diff.total_seconds() <= 1 : # To run it once a day
t.cancel()
countdown()
要在倒计时结束时打印 "Click Now",您可以这样做:
from datetime import datetime
import threading
selected_date = datetime(2017,3,25,4,4)
def countdown() :
t = threading.Timer(1.0, countdown)
t.start()
diff = (selected_date - datetime.now())
if diff.total_seconds() <= 1 : # To run it once a day
t.cancel()
print "Click Now"
else :
print diff.seconds
countdown()
这将导致这样的结果 每秒 :
2396
2395
2394
2393
...