如何自定义默认的 Boost xml 序列化默认节点命名以使其更具可读性

Question

下面的代码生成了一个 xml 文件，但是当它循环遍历一个地图时，它总是将地图键命名为 first，并将值命名为 second

有没有一种方法可以将标签名称 first 和 second 自定义为 groupid 和 groupType，如所需输出所示

 #include <fstream>
#include <boost/serialization/map.hpp>
#include <boost/serialization/nvp.hpp>
#include <boost/archive/xml_oarchive.hpp>
#include <string>
#include <iostream>
#include <map>

using namespace std;

class MyConnections
{
  public:
    MyConnections()
    {

       e_group.insert( std::make_pair(1,"ETOTO") ) ;
       e_group.insert( std::make_pair(2,"ETOTO") ) ;

   }

    template<class archive>
    void serialize(archive& ar, const unsigned int version)
    {
        using boost::serialization::make_nvp;
        ar & make_nvp("Connections", e_group);
    }

  public:
   typedef   map<int,std::string> groups;
   groups  e_group;
};

int main(int argc, char* argv[])
{
    std::ofstream ofs("output.xml");
    const MyConnections conn;
    boost::archive::xml_oarchive xml(ofs);
    xml << boost::serialization::make_nvp("Connections", conn);
}

当前输出：

     <?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<!DOCTYPE boost_serialization>
<boost_serialization signature="serialization::archive" version="14">
<Connections class_id="0" tracking_level="0" version="0">
        <Connections class_id="1" tracking_level="0" version="0">
                <count>2</count>
                <item_version>0</item_version>
                <item class_id="2" tracking_level="0" version="0">
                        <first>1</first>
                        <second>ETOTO</second>
                </item>
                <item>
                        <first>2</first>
                        <second>ETOTO</second>
                </item>
        </Connections>
</Connections>
</boost_serialization>

期望的输出

<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<!DOCTYPE boost_serialization>
<boost_serialization signature="serialization::archive" version="14">
<Connections class_id="0" tracking_level="0" version="0">
        <Connections class_id="1" tracking_level="0" version="0">
                <count>2</count>
                <item_version>0</item_version>
                <item class_id="2" tracking_level="0" version="0">
                        <groupid>1</groupid>
                        <groupType>ETOTO</groupType >
                </item>
                <item>
                        < groupid >2</groupid >
                        < groupType >ETOTO</groupType >
                </item>
        </Connections>
</Connections>
</boost_serialization>

Answer 1

地图的序列化是一种通用实现。

您当然可以提供/更好的匹配/并覆盖命名：

namespace boost { namespace serialization { 
    template <typename Ar>
        void serialize(Ar& ar, std::pair<int const, std::string>& p, unsigned) {
            ar & make_nvp("groupid", p.first) & make_nvp("groupType", p.second);
        }
} }

看到了Live On Coliru

这会打印（摘录）：

<Connections class_id="1" tracking_level="0" version="0">
    <count>2</count>
    <item_version>0</item_version>
    <item class_id="2" tracking_level="0" version="0">
        <groupid>1</groupid>
        <groupType>ETOTO</groupType>
    </item>
    <item>
        <groupid>2</groupid>
        <groupType>ETOTO</groupType>
    </item>
</Connections>

当然，这有问题int -> string的所有地图都获得相同的命名，所以一定要看看http://www.boost.org/doc/libs/1_63_0/libs/serialization/doc/strong_typedef.html

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I'd suggest that if you want/need this level of control, you shouldn't not be using XML archive.

如何自定义默认的 Boost xml 序列化默认节点命名以使其更具可读性

how to customise default Boost xml Serialisation default node naming to make it more readable

c++11

boost

xml-serialization

boost-spirit

boost-serialization

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