如何创建与我的 php 函数执行类似工作的过程（优化加速）

Question

我得到了 table 如下所示

mysql> select * from dts;
+----+------+------+--------+------+------+------+------+------+
| Id | key1 | key2 | serial | pr1  | pr2  | pr3  | pr4  | pr5  |
+----+------+------+--------+------+------+------+------+------+
|  1 |    1 |    1 |      1 |    0 |    0 |    1 |    0 |    2 |
|  2 |    1 |    1 |      2 |    0 |    0 |    0 |    0 |    0 |
|  3 |    1 |    1 |      3 |    0 |    0 |    0 |    1 |    0 |
|  4 |    1 |    1 |      4 |    1 |    0 |    1 |    1 |    3 |
|  5 |    1 |    2 |      5 |    0 |    0 |    0 |    2 |    5 |
|  6 |    1 |    2 |      6 |    0 |    0 |    0 |    0 |    1 |
|  7 |    1 |    2 |      7 |    0 |    1 |    0 |    0 |    0 |
|  8 |    2 |    2 |      1 |    1 |    1 |    1 |    1 |    2 |
|  9 |    2 |    2 |      2 |    0 |    0 |    0 |    0 |    0 |
| 10 |    3 |    2 |      3 |    0 |    0 |    0 |    0 |    0 |
| 11 |    3 |    3 |      1 |    1 |    1 |    0 |    0 |    1 |
| 12 |    3 |    3 |      5 |    0 |    0 |    1 |    1 |    0 |
+----+------+------+--------+------+------+------+------+------+
12 rows in set (0.00 sec)

我想将 key1、key2、db、table 和逗号分隔的字段列表传递给过程，并希望从这些字段中搜索记录的非零值 returned通过 select 语句，如果假设如果我得到所有非零字段，则中断循环并返回 return 字符串。

下面是我尝试使用 php

function show_available($key1, $key2, $db, $table, $conn, $fields=null) 
{

/* Select all fields in argument from db table where key... */
$query = "select ".$fields." FROM $db.$table where key1=$key1 and key2=$key2";

/* Query */
$result = $conn->query($query , MYSQLI_USE_RESULT);

/* Output array  */
$out = array();
while($row=$result->fetch_assoc())
{
    /* Loop through fields */
    foreach($row as $key => $val)
    {
        /* If val is greater than 0*/
        if($val > 0 ){

            /*Ok we got field which has value greater than 0*/
            $out[$key]=1;   
        }       
    }
    /* If all fields are found ok in so many records where key1=x and key2=x, break loop */
    if(count($out) == count($field_arr))break;
}

/* Return which all fields has value greater than 0 */
return implode(',', array_keys($out));

 }

在同一个函数中，我想转换成程序来加速我的任务，并希望得到如下输出，怎么可能，请帮助某人

如果我通过 someprocedure(1,1,db,table,'pr1,pr2,pr3,pr4,pr5') 我想得到输出 pr1,pr3,pr4,pr5 因为当 key1=1 和 key2=1

+----+------+------+--------+------+------+------+------+------+
| Id | key1 | key2 | serial | pr1  | pr2  | pr3  | pr4  | pr5  |
+----+------+------+--------+------+------+------+------+------+
|  1 |    1 |    1 |      1 |    0 |    0 |    1 |    0 |    2 | - Found pr3,pr5
|  2 |    1 |    1 |      2 |    0 |    0 |    0 |    0 |    0 |
|  3 |    1 |    1 |      3 |    0 |    0 |    0 |    1 |    0 | - Found pr4
|  4 |    1 |    1 |      4 |    1 |    0 |    1 |    1 |    3 | - Found pr1

同样适用于 key1=2 和 key2=2

|  8 |    2 |    2 |      1 |    1 |    1 |    1 |    1 |    2 | - Found pr1-pr5, break loop and return string
|  9 |    2 |    2 |      2 |    0 |    0 |    0 |    0 |    0 |

预期输出

# For procedure call expected o/p
key1       key2 fields_non_zero
1           1   pr1,pr3,pr4,pr5

1           2   pr2,pr4,pr5

2           2   pr1,pr2,pr3,pr4,pr5

3           2

3           3   pr1,pr2,pr3,pr4,pr5

table转储

DROP TABLE IF EXISTS `dts`;
CREATE TABLE `dts` (
  `Id` int(11) NOT NULL AUTO_INCREMENT,
  `key1` int(11) DEFAULT '-99',
  `key2` int(11) DEFAULT '-99',
  `serial` int(11) DEFAULT '-99',
  `pr1` int(11) DEFAULT '-99',
  `pr2` int(11) DEFAULT '-99',
  `pr3` int(11) DEFAULT '-99',
  `pr4` int(11) DEFAULT '-99',
  `pr5` int(11) DEFAULT '-99',
  PRIMARY KEY (`Id`),
  KEY `main` (`key1`,`key2`,`serial`)
) ENGINE=MyISAM AUTO_INCREMENT=13 DEFAULT CHARSET=latin1;


LOCK TABLES `dts` WRITE;
INSERT INTO `dts` VALUES (1,1,1,1,0,0,1,0,2),(2,1,1,2,0,0,0,0,0),(3,1,1,3,0,0,0,1,0),(4,1,1,4,1,0,1,1,3),(5,1,2,5,0,0,0,2,5),(6,1,2,6,0,0,0,0,1),(7,1,2,7,0,1,0,0,0),(8,2,2,1,1,1,1,1,2),(9,2,2,2,0,0,0,0,0),(10,3,2,3,0,0,0,0,0),(11,3,3,1,1,1,0,0,1),(12,3,3,5,0,0,1,1,0);
UNLOCK TABLES;

Answer 1

您需要的是 max（或 sum）与 concat_ws:

的聚合

select
    key1, key2, 
    concat_ws(
        ',',
        case when max(pr1) <> 0 then 'pr1' end,
        case when max(pr2) <> 0 then 'pr2' end,
        case when max(pr3) <> 0 then 'pr3' end,
        case when max(pr4) <> 0 then 'pr4' end,
        case when max(pr5) <> 0 then 'pr5' end
    ) as val
from dts
group by key1, key2;

产生：

key1    key2    val
1       1       pr1,pr3,pr4,pr5
1       2       pr2,pr4,pr5
2       2       pr1,pr2,pr3,pr4,pr5
3       2       
3       3       pr1,pr2,pr3,pr4,pr5

如何创建与我的 php 函数执行类似工作的过程（优化加速）

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