Django 外键下拉
Django foreign key drop down
Django 和 Python 的新手,我需要一些外键下拉方面的帮助。基本上,我有一个类别模型和一个图像模型,我希望用户能够选择将图像放入哪个类别。如何在图像表单中为类别创建下拉列表?我的观点和html也正确吗?我在网上看过,但我自己似乎做不到。我不断收到错误消息。
这是我的模型:
class Images(models.Model):
image = models.ImageField(upload_to='images', blank=False)
img_name = models.CharField(max_length=120, blank=True)
img_date = models.DateTimeField(default=now())
img_user = models.ForeignKey(User)
img_cat_id = models.ForeignKey(Categories)
def __unicode__(self):
return self.img_name
class Categories(models.Model):
cat_descr = models.CharField(max_length =120, blank=False)
def __unicode__(self):
return self.cat_descr
观看次数:
@login_required
def upload_images(request):
context = RequestContext(request)
context_dict={}
if request.method == 'POST': # render the form, and throw it back.
# take the form data and process it!
form = UploadImagesForm(request.POST, request.FILES)
if form.is_valid():
print 'form is_valid'
upload_image = form.save(commit=False)
upload_image.img_user = request.user
if 'image' in request.FILES:
upload_image.image =request.FILES['image']
upload_image.save()
return render(request, 'rmb/upload.html', {'upload_image': form})
else:
print form.errors
# Not a HTTP POST, so we render our form using two ModelForm instances.
# These forms will be blank, ready for user input.
else:
form = UploadImagesForm()
context_dict = {'upload_image': form}
all_categories = Categories.objects.order_by('-id')
context_dict['all_categories'] = all_categories
print context_dict
return render_to_response('rmb/upload.html', context_dict, context)
表格:
class UploadImagesForm(forms.ModelForm):
#cat_list = ModelChoiceField(queryset=Categories.objects.all())
class Meta:
model = Images
fields=('image','img_name')
HTML:
{% block body_block %}
<form id="upload_form" method="post" action="/rmb/upload/"
enctype="multipart/form-data">
{% csrf_token %}
{{ upload_image.as_table }}
<input type="submit" name="submit" value="Upload" />
{% for categories in all_categories %}
<div> {{ categories.id }} </div>
{{ categories.cat_descr }}
<input type="submit" name="submit" value="Upload" />
{% endfor %}
</form>
{% endblock %}
You don't need to insert the HTML for the form manually, just use {{form}}
in the template.
{% block body_block %}
<form id="upload_form" method="post" action="/rmb/upload/"
enctype="multipart/form-data">
{% csrf_token %}
{{ form }}
</form>
{% endblock %}
By default a ForeignKey will be a select field 所以您不需要做太多其他事情。
顺便说一句,给你的模型和领域更合适的名字。我们知道这些都是图像场,因为它们在图像上并确保除非您的模型是事物的集合,否则您会给它一个单一的名称。最后,当使用外键时,项目会得到一个额外的 fieldname_id
字段,它只是 ID,而 fieldname
是 属性,它也提供相关项目。
所以代替:
class Images(models.Model):
image = models.ImageField(upload_to='images', blank=False)
img_name = models.CharField(max_length=120, blank=True)
img_date = models.DateTimeField(default=now())
img_user = models.ForeignKey(User)
img_cat_id = models.ForeignKey(Categories)
使用:
class Image(models.Model):
image = models.ImageField(upload_to='images', blank=False)
name = models.CharField(max_length=120, blank=True)
date = models.DateTimeField(default=now())
user = models.ForeignKey(User)
category = models.ForeignKey(Categories)
Django 和 Python 的新手,我需要一些外键下拉方面的帮助。基本上,我有一个类别模型和一个图像模型,我希望用户能够选择将图像放入哪个类别。如何在图像表单中为类别创建下拉列表?我的观点和html也正确吗?我在网上看过,但我自己似乎做不到。我不断收到错误消息。
这是我的模型:
class Images(models.Model):
image = models.ImageField(upload_to='images', blank=False)
img_name = models.CharField(max_length=120, blank=True)
img_date = models.DateTimeField(default=now())
img_user = models.ForeignKey(User)
img_cat_id = models.ForeignKey(Categories)
def __unicode__(self):
return self.img_name
class Categories(models.Model):
cat_descr = models.CharField(max_length =120, blank=False)
def __unicode__(self):
return self.cat_descr
观看次数:
@login_required
def upload_images(request):
context = RequestContext(request)
context_dict={}
if request.method == 'POST': # render the form, and throw it back.
# take the form data and process it!
form = UploadImagesForm(request.POST, request.FILES)
if form.is_valid():
print 'form is_valid'
upload_image = form.save(commit=False)
upload_image.img_user = request.user
if 'image' in request.FILES:
upload_image.image =request.FILES['image']
upload_image.save()
return render(request, 'rmb/upload.html', {'upload_image': form})
else:
print form.errors
# Not a HTTP POST, so we render our form using two ModelForm instances.
# These forms will be blank, ready for user input.
else:
form = UploadImagesForm()
context_dict = {'upload_image': form}
all_categories = Categories.objects.order_by('-id')
context_dict['all_categories'] = all_categories
print context_dict
return render_to_response('rmb/upload.html', context_dict, context)
表格:
class UploadImagesForm(forms.ModelForm):
#cat_list = ModelChoiceField(queryset=Categories.objects.all())
class Meta:
model = Images
fields=('image','img_name')
HTML:
{% block body_block %}
<form id="upload_form" method="post" action="/rmb/upload/"
enctype="multipart/form-data">
{% csrf_token %}
{{ upload_image.as_table }}
<input type="submit" name="submit" value="Upload" />
{% for categories in all_categories %}
<div> {{ categories.id }} </div>
{{ categories.cat_descr }}
<input type="submit" name="submit" value="Upload" />
{% endfor %}
</form>
{% endblock %}
You don't need to insert the HTML for the form manually, just use {{form}}
in the template.
{% block body_block %}
<form id="upload_form" method="post" action="/rmb/upload/"
enctype="multipart/form-data">
{% csrf_token %}
{{ form }}
</form>
{% endblock %}
By default a ForeignKey will be a select field 所以您不需要做太多其他事情。
顺便说一句,给你的模型和领域更合适的名字。我们知道这些都是图像场,因为它们在图像上并确保除非您的模型是事物的集合,否则您会给它一个单一的名称。最后,当使用外键时,项目会得到一个额外的 fieldname_id
字段,它只是 ID,而 fieldname
是 属性,它也提供相关项目。
所以代替:
class Images(models.Model):
image = models.ImageField(upload_to='images', blank=False)
img_name = models.CharField(max_length=120, blank=True)
img_date = models.DateTimeField(default=now())
img_user = models.ForeignKey(User)
img_cat_id = models.ForeignKey(Categories)
使用:
class Image(models.Model):
image = models.ImageField(upload_to='images', blank=False)
name = models.CharField(max_length=120, blank=True)
date = models.DateTimeField(default=now())
user = models.ForeignKey(User)
category = models.ForeignKey(Categories)