Javascript 数组组合元素以获得唯一数组

Question

假设我有一个这样的 JS 数组：

[
  {
    "lat": 49.26125,
    "lon": -123.24807,
    "weight": 120
  },
  {
    "lat": 49.26125,
    "lon": -123.24807,
    "weight": 80
  },
  {
    "lat": 49.26125,
    "lon": -123.24807,
    "weight": 160
  },
  {
    "lat": 49.26229,
    "lon": 23.24342,
    "weight": 236
  },
  {
    "lat": 49.26229,
    "lon": 23.24342,
    "weight": 167
  }
]

假设我想将具有相同 lat 和 lon[= 的元素相加 weights 22=] 得到这样的东西：

[ { "lat": 49.26125, "lon": -123.24807, "weight": 360 }, { "lat": 49.26229, "lon": 23.24342, "weight": 403 } ]

在 JS 中执行此操作的有效方法是什么？

Answer 1

您可以使用散列 table 作为闭包，并使用包含 lat 和 lon 的键作为组合值。

然后检查散列是否存在，如果不存在则用数据生成一个新对象并将其推送到结果集。

稍后将 weight 添加到散列对象的属性。

var data = [{ lat: 49.26125, lon: -123.24807, weight: 120 }, { lat: 49.26125, lon: -123.24807, weight: 80 }, { lat: 49.26125, lon: -123.24807, weight: 160 }, { lat: 49.26229, lon: 23.24342, weight: 236 }, { lat: 49.26229, lon: 23.24342, weight: 167 }],
    result = data.reduce(function (hash) {
        return function (r, a) {
            var key = ['lat', 'lon'].map(function (k) { return a[k]; }).join('|');
            if (!hash[key]) {
                hash[key] = { lat: a.lat, lon: a.lon, weight: 0 };
                r.push(hash[key]);
            }
            hash[key].weight += a.weight;
            return r;
        };
    }(Object.create(null)), []);

console.log(result);

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Answer 2

您可以通过 reduce-ing your array to form a map from unique [lat, lon] pairs to a merged object that accumulates your total weight. Your result is then the list of values held by that map (which can be obtained using Object.keys and Array#map).

var array = [{lat:49.26125,lon:-123.24807,weight:120},{lat:49.26125,lon:-123.24807,weight:80},{lat:49.26125,lon:-123.24807,weight:160},{lat:49.26229,lon:23.24342,weight:236},{lat:49.26229,lon:23.24342,weight:167}]

var map = array.reduce(function (map, o) {
  var k = [o.lat, o.lon].join()
  
  if (k in map)
    map[k].weight += o.weight
  else 
    map[k] = o
  
  return map
}, {})

var result = Object.keys(map).map(function (k) { return map[k] })

console.log(result)

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Answer 3

你可以这样做。它可能没有那么有效，但它确实有效。

var arr = [{ lat: 49.26125, lon: -123.24807, weight: 120 }, { lat: 49.26125, lon: -123.24807, weight: 80 }, { lat: 49.26125, lon: -123.24807, weight: 160 }, { lat: 49.26229, lon: 23.24342, weight: 236 }, { lat: 49.26229, lon: 23.24342, weight: 167 }];

arr = arr.reduce(function(accumulation, currentElement){
    var samePosition = accumulation.find(function(obj){
        return obj.lat === currentElement.lat && obj.lng === currentElement.lng;
    });
    if(samePosition){
        samePosition.weight += currentElement.weight;
    }else{
        accumulation.push(currentElement);
    }
    return accumulation;
}, []);

console.log(arr);

Javascript 数组组合元素以获得唯一数组

Javascript Array combine elements to get a unique array

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