Python:对pickle & getOpt的误解

Python: Misunderstanding of pickle & getOpt

我正在测试 pickling 和 getOpts,每一个都取得了成功,但现在我试图将两者结合起来,但遇到了麻烦。下面是我正在做的事情的片段,

#! /usr/bin/env python

from itertools import groupby, chain
import pickle
import getopt
import sys

def main():

    # default values
    var1 = 6
    var2 = 7
    var3 = 4

    try:
        opts, args = getopt.getopt(sys.argv[1:], 'l:z', ['load=', 'help'])
    except getopt.GetoptError:
        usage()
        sys.exit(2)

    for opt, arg in opts:
        if opt in ('-z', '--help'):
            usage()
            sys.exit(2)
        elif opt in ('-l', '--load'):
            pkl_file = open('data.pkl', 'rb')
            settings = pickle.load(pkl_file)
            var1 = settings[0]
            var2 = settings[1]
            var3 = settings[2]
            pkl_file.close()
        else:
            usage()
            sys.exit(2)

    print ("\nthe values are as follows")
    print ("cvar1: " + str(var1))
    print ("var2: " + str(var2))
    print ("var3: " + str(var3))

if __name__ == "__main__":
    main()

并且在酸洗数据时我使用以下代码

#! /usr/bin/env python

import pickle

settings =  [3, 15, 4]

output = open('data.pkl', 'wb')

# Pickle dictionary using protocol 0.
pickle.dump(settings, output)

output.close()

但是,当我尝试 运行 使用“-l”标志时,出现以下错误

NameError: global name 'usage' is not defined

知道为什么会这样吗?提前致谢!

您正在调用一个您尚未定义的函数 (usage())。你需要实现这个功能,否则你的代码不会' 运行.