如何将我的列表作为工具提示

How do I get my list in as a tooltip

在下面的代码中,我希望 GetChainDetails 中的 return 转到我在 GetChains 方法中有 "I WANT MY LIST HERE" 的位置。不确定如何完成或有什么其他方法可以做到这一点。

public static IEnumerable GetChains(int actGroupid, int dispid)
    {
        EEDBEntities db = new EEDBEntities();
        var query = from c in db.Chains                                              
                    where c.Activity_Basis.activity_group_id == actGroupid && c.Activity_Basis.discipline_id == dispid
                    select new
                    {
                        ChainID = c.ChainID,
                        ChainDesc =  @"<span data-toggle=""tooltip"" title =""" + I WANT MY LIST HERE + @""">" + c.ChainID + "</span>"
                    };            
        return query.ToList();
    }

    public string GetChainDetails(string chainID)
    {
        string sStep = null;
        var chainDetailList = from c in db.Chains_Detail
                              where c.chainID == chainID
                              orderby c.Order
                              select new
                              {
                                  Order = c.Order,
                                  Step = c.Step
                              };
        foreach (var oItem in chainDetailList.ToList())
        {
            sStep = sStep + "\n" + oItem.Order + ": " + oItem.Step;
        }
        return sStep;
    }

你的方法public string GetChainDetails(string chainID) 不是静态的。也许这就是您出错的原因。将其设为静态并尝试 运行 代码。

public static string GetChainDetails(string chainID)

你也可以按照这个方法:

class X
    {
        public int Property1;
        public int Property2;

        public string ChainID;
        public string MyListToolTipText;
    }

    class Y
    {
        public string ChainID;
        public string ChainDesc;
    }

还有你的主要代码

class Program
    {
    static void Main()
    {
        var myResult = GetChains(1, 1);
        foreach (var result in myResult)
        {
            result.ChainDesc = GetChainDetails(result.ChainID);
        }
        //you can use either foreach or linq
        //var m = myResult.Select(result => result = new Y { ChainID = result.ChainID, ChainDesc = GetChainDetails(result.ChainDesc) });
    }

    public static IEnumerable<Y> GetChains(int actGroupid, int dispid)
    {
        var Chains = new List<X>();
        var query = from c in Chains                                              
                    where c.Property1 == actGroupid && c.Property2 == dispid
                    select new Y
                    {
                        ChainID = c.ChainID,
                        ChainDesc =  @"<span data-toggle=""tooltip"" title =""" + c.MyListToolTipText + @""">" + c.ChainID + "</span>"
                    };            
        return query.ToList<Y>();
    }

    public static string GetChainDetails(string chainID)
    {
        string sStep = null;
        var chainDetailList = from c in db.Chains_Detail
                              where c.chainID == chainID
                              orderby c.Order
                              select new
                              {
                                  Order = c.Order,
                                  Step = c.Step
                              };
        foreach (var oItem in chainDetailList.ToList())
        {
            sStep = sStep + "\n" + oItem.Order + ": " + oItem.Step;
        }
        return sStep;
    }
}   

因此在调用 GetChains 之后,我正在修改每个成员 属性。