2个函数的平均值

Question

当我运行这段代码时，我似乎一直偏离平均水平，想知道是否有人有任何建议，我尝试了一个例子，就是让 5 名员工全部缺勤 5 天，并保持平均 15 ，我算错了吗？再次感谢您的帮助。我发布了完整的代码，以防万一它不是我试图让它尽可能整洁的功能，如果它在不到一个月的时间里有点乱，我很抱歉。

#include<iostream>
using namespace std;

function prototypes

//return type: void
//parameter type: 1 int by refrence
//purpose: This function asks the user for the number of employees in the company.
void GetNumEmployees(int&);

//return type: int
//parameter type: 1 int
//Purpose: The function should as the user to enter the number of days each employee missed during the past year
int TotalDaysMissed(int);

//return type: float
//parameters: 2 int
//Purpose: Returns the average of total number of days missed for all employees in the company during the year
float AverageDaysMissed(int, int);

int main()
{
    //Declare and Initilize Variables
    int empnum = 0, daysmissed = 0 ;
    float averagedays = 0.0 ;
    GetNumEmployees(empnum) ;
    daysmissed = TotalDaysMissed(empnum)    ;
    averagedays = AverageDaysMissed(empnum, daysmissed) ;
    cout<<"The Average Work Days your Employees Missed is "<<averagedays<<endl ;
    return 0;
}
//function definitions
void GetNumEmployees(int &emp)
{
    do
    {
        cout<<"Enter the number of Employees in the company: ";
        cin>>emp ;
        if(emp < 1)
            cout<<"Invalid. Cannot be Less than 1\n\n";
    }
    while (emp < 1) ;
}

int TotalDaysMissed(int empn)
{
    int daysmissed = 0 ;
    int total = 0 ;
    for(int n = empn; n > 0  ; n--)
    {
        do
        {
            cout<<"How Many days did Employee "<<n<< " miss? " ;
            cin>>daysmissed ;
            total += daysmissed;
            if(daysmissed < 0)
                cout<<"Invalid days must be a Positive Number\n\n";
        }
        while(daysmissed < 0) ;
    }
    return total;
}

float AverageDaysMissed(int empn, int daystotal)
{
    float average = 0.0     ;
    average = (empn + daystotal) / 2.0 ;
    return average;
}

Answer 1

您计算的平均值不正确。

您有 5 名员工，每人缺勤 5 天。

(5 + 5 + 5 + 5 + 5) / 5 = 5

你的平均值是 5。

因此，如果您有 5 名员工按以下顺序缺勤：4、3、2、4、5。那么你的平均值 = (4 + 3 + 2 + 4 +5) / 5 = 3.6

平均值是所有观察值的总和除以观察值的数量。

2个函数的平均值

Average of 2 functions

c++

function

average