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Question

这是我的介绍程序class的一个片段，它在打开之前一直崩溃。它在第 12 行给出了语法错误，但我不知道如何修复它。

#defines the median
def median(data)
    data=sorted(data)
#this happens if there is an odd amount of numbers in the count
    if len(data)%2==1:
        return(data[int((count-1)/2)])
#this happens if there is an even amount of numbers in the count
    else:
        return(data(int[((count-1/2)+(count+1/2)/2]))
count=0
#Creates a dictionary loop that inputs all numbers in the list
for data
    numbers{count+=0}:
        else
        break
    for number in numbers:
        count=numbers[number]

Answer 1

尝试

#defines the median
def median(data)
    data=sorted(data)
#this happens if there is an odd amount of numbers in the count
    if len(data)%2==1:
        return(data[int((count-1)/2)])
#this happens if there is an even amount of numbers in the count
    else:
        return(data(int[((count-1/2)+(count+1/2)/2]))
count=0
#Creates a dictionary loop that inputs all numbers in the list
for data # in what:
    numbers{count+=1}: #your problem was that you weren't updating count 0+0 = 0
        else
        break
    for number in numbers:
        count=numbers[number]

Answer 2

看起来您的 for 循环在语法上不正确。应该类似于 for d in data:

另请参阅 Python for 循环的解释： https://wiki.python.org/moin/ForLoop