while 循环没有按预期继续

Question

出于某种原因，一旦我输入要搜索的字符，main 中的 while 循环就会终止，但目的是让您能够输入一行，然后输入一个字符进行搜索，直到您输入一个空行（输入没有什么）。基本上我想无限地执行第 1 步和第 2 步，直到我什么都不输入并按回车键。为什么这不起作用？感谢任何人的帮助！

另外，一个小问题，输入字符进行搜索后如何清除垃圾？

#include <stdio.h>
#define SIZE 41
int CharIsAt(char *pStr,char ch,int loc[],int mLoc);
int main(void){
    char array[SIZE],search;
    int found[SIZE],i,charsFound;
    //Step 1
    printf("Enter a line of text(empty line to quit): "); 
    while (fgets(array,SIZE, stdin)!=NULL && array[0]!='\n'){ //Loop until nothing is entered
    //Step 2
        printf("Enter a character to search: ");
        search=getchar();
        charsFound=CharIsAt(array,search,found,SIZE);
        printf("Entered text: ");
        fputs(array,stdout);
        printf("Character being searched for: %c\n",search);
        printf("Character found at %d location(s).\n",charsFound);
        for (i=0;i<charsFound;i++)
            printf("%c was found at %d\n",search,found[i]);
        printf("Enter a line of text(empty line to quit): ");
    }
    return 0;
}
int CharIsAt(char *pStr,char ch,int loc[],int mLoc){
    //Searches for ch in *pStr by incrementing a pointer to access
    //and compare each character in *pStr to ch.
    int i,x;
    for (i=0,x=0;i<mLoc;i++){
        if (*(pStr+i)==ch){
            //Stores index of ch's location to loc
            loc[x]=i;
            x++;    //Increment for each time ch was counted in pStr
        }
    }
    //Returns the number of times ch was found
    return x;
}

如果这不太烦人的话，我已经包含了我的全部代码，如果有帮助的话，我可以尝试制作一个更简单的问题版本。我认为发布整个代码可能对回答问题更有用。

再次感谢，干杯！

Answer 1

   while (fgets(array,SIZE, stdin)!=NULL && array[0]!='\n'){
        printf("Enter a character to search: ");
        search=getchar();
        charsFound=CharIsAt(array,search,found,SIZE);
        printf("Entered text: ");
        fputs(array,stdout);
        printf("Character being searched for: %c\n",search);
        printf("Character found at %d location(s).\n",charsFound);
        for (i=0;i<charsFound;i++)
            printf("%c was found at %d\n",search,found[i]);
        if (fgets(array,SIZE, stdin)==NULL) break;
    }
    return 0;

这应该有效

Answer 2

已发布代码的主要问题是用户必须按 enter 才能将 search 字符输入程序。然而，对 getchar() 的调用只消耗了一个字符，因此它没有消耗换行符序列。

要解决此问题，请循环调用 getchar() 直到字符为 EOF 或 '\n' 以清空 stdin 的 any/all 剩余垃圾。

然后回到循环的顶部

while 循环没有按预期继续

The while loop doesn't continue as intended

c

arrays

fgets

while-loop

garbage