GROUP_CONCAT 个 SUM

Question

我有两个 select 查询都给出了正确的结果：

SELECT SUM(value) AS "sum1" FROM table GROUP BY id1

和

SELECT SUM(value) AS "sum2" FROM table GROUP BY id1, id2

sum1 是所有 sum2 项目的总和，我想要一个查询，它给我的结果是 sum1 和所有 [=15] 的 GROUP_CONCAT =]-项目。但是如何在 GROUP_CONCAT 中为 sum2-items 元素定义 GROUP BY？

SELECT SUM(value) AS "sum1", GROUP_CONACAT(SUM(value) AS "sum2" ... (?))
FROM table GROUP BY id1

Answer 1

你应该使用子查询来解决它，使用下面的查询，我相信它会解决你的问题

select sum(t.part_sum) as sum1, group_concat(t.part_sum) as sum2 from (select sum(value) as part_sum from table group by id1, id2) as t