JavaFX:为满足条件的 ObservableList 设置计数限制

JavaFX: Setting count limit for an ObservableList fulfilling a condition

我举个例子来说明。

public class Person
{
    private final ObjectProperty<Gender> gender;
    public final ObjectProperty<Gender> genderProperty()
    {
        return this.gender;
    }
    public final void setGender(Gender value)
    {
        this.genderProperty().set(value);
    }
    public final Gender getGender()
    {
        return this.genderProperty().get();
    }

    public static enum Gender { MALE, FEMALE }

    /* Other properties */
}

其他地方...

public class MyClass
{
    private final ObservableList<Person> people;
    public final ObservableList<Person> getPeople()
    {
        return this.people;
    }

    public MyClass()
    {
        // Create observable arraylist with extractor
        this.people = FXCollections.observableArrayList(
            person -> new Observable[]
                {
                    person.genderProperty()
                }
            );
    }
}

我需要 people 列表最多包含 10 个男性和最多 5 个女性。某些Person对象在添加到people列表时没有gender信息,但我的应用程序必须:

  1. 当其中一个 Person 对象更改其 gender 时,选择这样的更改,并且该更改恰好违反了此限制。
  2. 撤消这样的更改,这样我的 10 男/5 女限制规则将始终适用。

我能做些什么来确保这一点?

首先,您可以在 Gender 中添加一个代表未知性别的新枚举值:

public enum Gender { MALE, FEMALE, UNKNOWN }.

然后你可以使用 ListChangeListener 比如:

this.people = FXCollections.observableArrayList(person -> new Observable[] {person.genderProperty()});

 ListChangeListener<Person> listener = new ListChangeListener<Person>() {

    private boolean checkCondition(ObservableList<Person> list, Person.Gender gender) {
        int males = 0;
        int females = 0;

        for (Person person : list) {
            switch (person.getGender()) {
                case MALE: males++; break;
                case FEMALE: females++; break;
                default: break;
            }
        }

        return ((males > 10 && gender == Person.Gender.MALE) ||
                (females > 5 && gender == Person.Gender.FEMALE));
    }

    @Override
    public void onChanged(Change<? extends Person> c) {
        while (c.next()) {
            if (c.wasAdded()) {
                for (Person person : c.getAddedSubList()) {
                    if (checkCondition((ObservableList<Person>) c.getList(), person.getGender()))
                        c.getList().remove(person);
                }
            }
            if (c.wasUpdated()) {
                for (int update = c.getFrom(); update < c.getTo(); update++) {
                    Person person = c.getList().get(update);
                    if (checkCondition((ObservableList<Person>) c.getList(), person.getGender()))
                        person.setGender(Person.Gender.UNKNOWN);
                }

            }
        }
    }
};

people.addListener(listener);

此解决方案的唯一问题是,它实际上并没有 "revert" 更新更改,而是将性别设置为新的未知值。


如果你真的想恢复更改,解决方案可以是这样的:

this.people = FXCollections.observableArrayList();

 ListChangeListener<Person> listener = new ListChangeListener<Person>() {

    private boolean checkCondition(ObservableList<Person> list, Person.Gender gender) {
        int males = 0;
        int females = 0;

        for (Person person : list) {
            switch (person.getGender()) {
                case MALE: males++; break;
                case FEMALE: females++; break;
                default: break;
            }
        }

        return ((males > 10 && gender == Person.Gender.MALE) ||
                (females > 5 && gender == Person.Gender.FEMALE));
    }

    @Override
    public void onChanged(Change<? extends Person> c) {
        while (c.next()) {
            if (c.wasAdded()) {
                for (Person person : c.getAddedSubList()) {

                    if (checkCondition((ObservableList<Person>) c.getList(), person.getGender()))
                        c.getList().remove(person);
                    else
                        person.genderProperty().addListener((obs, oldval, newval) -> {
                            if (checkCondition((ObservableList<Person>) c.getList(), newval))
                                person.setGender(oldval);
                        });
                }
            }
        }
    }
};

people.addListener(listener);

差异:提取器已被删除,因为在 ListChangeListener 内部仅包含元素的添加。当添加一个新元素时,其 genderProperty 上的侦听器已被添加,该侦听器检查性别更新,如果不满足条件,则该基因将恢复为原始基因。


您也可以通过不公开列表,而是公开操作列表的方法来实现相同的功能:addPersonAtremovePersonAtupdateGenderAt