Android Wear Volley onResponse 错误 null
Android Wear Volley onResponse error null
我正在尝试使用我的 Sony Smartwatch 3 从 AWS 获取数据。但是,在使用 Volley 处理数据时,我总是得到 "Error: null"。它可以在我的 android 智能手机上使用确切的一些代码运行,但在智能手表上遇到错误。
这是我的 activity 代码
button2 = (Button) findViewById(R.id.button2);
button2.setOnClickListener(new View.OnClickListener(){
@Override
public void onClick(View v) {
getTemperature();
//displaySpeechRecognizer();
}
});
还有我的截击代码
private void getTemperature() {
// Tag used to cancel the request
String tag_string_req = "req_login";
pDialog.setMessage("Getting data ...");
showDialog();
StringRequest strReq = new StringRequest(Request.Method.GET,
AppConfig.URL_TEMPERATURE, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.d(TAG, "AWS-Response: " + response.toString());
hideDialog();
try {
JSONObject jObj = new JSONObject(response);
JSONObject user = jObj.getJSONObject("user");
String temperature = user.getString("value");
String humidity = user.getString("value2");
String totals = "The temperature is "+temperature+" and humidity is "+humidity;
total.setText(totals);
} catch (JSONException e) {
// JSON error
e.printStackTrace();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.e(TAG, "AWS Error: " + error.getMessage());
hideDialog();
}
});
// Adding request to request queue
AppController.getInstance().addToRequestQueue(strReq, tag_string_req);
}
这是预期的 JSON 响应
{"user":{"value":"23.0","value2":"41.0"}}
和当前错误
04-04 15:32:49.229 27078-27078/com.sp.weargetfromaws E/MainActivity: AWS Error: null
和 php 文件
<?php
// json response array
$response = array();
$config = parse_ini_file('./private/config.ini');
$link = mysqli_connect($config['servername'],$config['username'],$config['password'],$config['dbname']);
$tablename = $config['tablenamevalue'];
$sql = "SELECT * FROM ".$tablename." WHERE serialno = 'a' ORDER BY ID DESC LIMIT 1 ";
if($result = mysqli_query($link, $sql))
{
if(mysqli_num_rows($result) > 0)
{
while($row = $result->fetch_array(MYSQLI_BOTH))
{
$response["user"]["value"] = $row["value"];
$response["user"]["value2"] = $row["value2"];
}
echo json_encode($response);
}
}
?>
如果您不需要使用 GET 方法将任何值推送到您的 API 代码,请尝试 JsonArrayRequest
您的 php 文件:
$config = parse_ini_file('./private/config.ini');
$link = mysqli_connect($config['servername'],$config['username'],$config['password'],$config['dbname']);
$tablename = $config['tablenamevalue'];
$sql = "SELECT * FROM ".$tablename." WHERE serialno = 'a' ORDER BY ID DESC LIMIT 1 ";
$result = mysqli_query($link,$sql);
$res = array();
while($row = mysqli_fetch_array($result)){
array_push($res, array(
"value1"=>$row['value1'],
"value2"=>$row['value2'],
));
}
echo json_encode($res, JSON_PRETTY_PRINT | JSON_UNESCAPED_UNICODE | JSON_ERROR_UTF8);
你的排球代码:
private void getTemperature() {
// Tag used to cancel the request
String tag_string_req = "req_login";
pDialog.setMessage("Getting data ...");
showDialog();
JsonArrayRequest jsonArrayRequest = new JsonArrayRequest(AppConfig.URL_TEMPERATURE,
new Response.Listener<JSONArray>() {
@Override
public void onResponse(JSONArray response) {
parseData(response);
progressBar.setVisibility(View.GONE);
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(getActivity().getApplicationContext(), "Thats all", Toast.LENGTH_SHORT).show();
//Hiding the progressbar
}
});
return jsonArrayRequest;
}
private void parseData(JSONArray array) {
String temperature = null;
String humidity = null;
String totals = null;
Log.d("DebugTag", "Value array.length() - parseData:" + array.length());
for (int i = 0; i < array.length(); i++) {
JSONObject json = null;
try {
//Getting json
json = array.getJSONObject(i);
temperature = json.getString("value1");
humidity = json.getString("value2");
totals = "The temperature is "+temperature+" and humidity is "+humidity;
} catch (JSONException e) {
e.printStackTrace();
}
}
total.setText(totals);
}
我正在尝试使用我的 Sony Smartwatch 3 从 AWS 获取数据。但是,在使用 Volley 处理数据时,我总是得到 "Error: null"。它可以在我的 android 智能手机上使用确切的一些代码运行,但在智能手表上遇到错误。
这是我的 activity 代码
button2 = (Button) findViewById(R.id.button2);
button2.setOnClickListener(new View.OnClickListener(){
@Override
public void onClick(View v) {
getTemperature();
//displaySpeechRecognizer();
}
});
还有我的截击代码
private void getTemperature() {
// Tag used to cancel the request
String tag_string_req = "req_login";
pDialog.setMessage("Getting data ...");
showDialog();
StringRequest strReq = new StringRequest(Request.Method.GET,
AppConfig.URL_TEMPERATURE, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.d(TAG, "AWS-Response: " + response.toString());
hideDialog();
try {
JSONObject jObj = new JSONObject(response);
JSONObject user = jObj.getJSONObject("user");
String temperature = user.getString("value");
String humidity = user.getString("value2");
String totals = "The temperature is "+temperature+" and humidity is "+humidity;
total.setText(totals);
} catch (JSONException e) {
// JSON error
e.printStackTrace();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.e(TAG, "AWS Error: " + error.getMessage());
hideDialog();
}
});
// Adding request to request queue
AppController.getInstance().addToRequestQueue(strReq, tag_string_req);
}
这是预期的 JSON 响应
{"user":{"value":"23.0","value2":"41.0"}}
和当前错误
04-04 15:32:49.229 27078-27078/com.sp.weargetfromaws E/MainActivity: AWS Error: null
和 php 文件
<?php
// json response array
$response = array();
$config = parse_ini_file('./private/config.ini');
$link = mysqli_connect($config['servername'],$config['username'],$config['password'],$config['dbname']);
$tablename = $config['tablenamevalue'];
$sql = "SELECT * FROM ".$tablename." WHERE serialno = 'a' ORDER BY ID DESC LIMIT 1 ";
if($result = mysqli_query($link, $sql))
{
if(mysqli_num_rows($result) > 0)
{
while($row = $result->fetch_array(MYSQLI_BOTH))
{
$response["user"]["value"] = $row["value"];
$response["user"]["value2"] = $row["value2"];
}
echo json_encode($response);
}
}
?>
如果您不需要使用 GET 方法将任何值推送到您的 API 代码,请尝试 JsonArrayRequest
您的 php 文件:
$config = parse_ini_file('./private/config.ini');
$link = mysqli_connect($config['servername'],$config['username'],$config['password'],$config['dbname']);
$tablename = $config['tablenamevalue'];
$sql = "SELECT * FROM ".$tablename." WHERE serialno = 'a' ORDER BY ID DESC LIMIT 1 ";
$result = mysqli_query($link,$sql);
$res = array();
while($row = mysqli_fetch_array($result)){
array_push($res, array(
"value1"=>$row['value1'],
"value2"=>$row['value2'],
));
}
echo json_encode($res, JSON_PRETTY_PRINT | JSON_UNESCAPED_UNICODE | JSON_ERROR_UTF8);
你的排球代码:
private void getTemperature() {
// Tag used to cancel the request
String tag_string_req = "req_login";
pDialog.setMessage("Getting data ...");
showDialog();
JsonArrayRequest jsonArrayRequest = new JsonArrayRequest(AppConfig.URL_TEMPERATURE,
new Response.Listener<JSONArray>() {
@Override
public void onResponse(JSONArray response) {
parseData(response);
progressBar.setVisibility(View.GONE);
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Toast.makeText(getActivity().getApplicationContext(), "Thats all", Toast.LENGTH_SHORT).show();
//Hiding the progressbar
}
});
return jsonArrayRequest;
}
private void parseData(JSONArray array) {
String temperature = null;
String humidity = null;
String totals = null;
Log.d("DebugTag", "Value array.length() - parseData:" + array.length());
for (int i = 0; i < array.length(); i++) {
JSONObject json = null;
try {
//Getting json
json = array.getJSONObject(i);
temperature = json.getString("value1");
humidity = json.getString("value2");
totals = "The temperature is "+temperature+" and humidity is "+humidity;
} catch (JSONException e) {
e.printStackTrace();
}
}
total.setText(totals);
}