strptime 如何解析：01/Jul/1995:00:00:01-0400

Question

我已经尝试了很多选项，并通过一些拼凑的解析来解决问题，但我很好奇如何使用 strptime 执行此操作？

item = "01/Jul/1995:00:00:01-0400"

checkdate = datetime.strptime(item,"%Y-%m-%dT:%H:%M%S%z")
checkdate = datetime.strptime(item,"%Y/%m/%dT:%H:%M:%S%z")
checkdate = datetime.strptime(item,"%Y-%b-%d:%H:%M%S%z")
checkdate = datetime.strptime(item,"%Y-%b-%dT:%H:%M:%S%z")
checkdate = datetime.strptime(item,"%Y/%m/%d:%H:%M:%S%z")

我每次尝试得到的是：

ValueError: time data '01/Jul/1995:00:00:01-0400' does not match format '%Y/%m/%d:%H:%M:%S%z'

正确的 strptime 格式是什么？

编辑：所以你是对的，我做了一个小测试

def split_date (stringdate):    
     datepart = [] 
     monthDict = {'Jan':'01','Feb':'02','Mar':'03','Apr':'04','May':'05',
 'Jun':'06','Jul':'07','Aug':'08','Sep':'09','Oct':'10','Nov':'11','Dec':'12'}
    split1 = [part for part in stringdate.split('/')]
    day = split1[0]
    month = split1[1]
    month = monthDict.get(month)
    split2 = [part for part in split1[2].split(":")]
    year = split2[0]
    hour = split2[1]
    minute = split2[2]
    split3 = [part for part in split2[3].split('-')]
    second = split3[0]
    timezone = split3[1]
    return datetime(int(year), int(month), int(day), int(hour), int(minute), int(second), int(timezone)

datetime_received_split = []
datetime_received_strp = []
s = time.time()
for date in data.time_received:
    try: 
        datetime_received_split.append(split_date(date))
    except:
        split_fail.append(date)
e = time.time()
print ('split took {} s '.format(e-s))
s = time.time() 
for date in data.time_received:
    try: 
             datetime_received_strp.append(datetime.strptime(item,"%d/%b/%Y:%H:%M:%S-     %f"))
    except: 
        strp_fail.append(date)
e = time.time() 
print ('strp took {} s'.format(e-s))

我发现手动拆分实际上要快很多？

Answer 1

%z is supported in Python 3.2+.

所以对于 Python2.x，看看 How to parse dates with -0400 timezone string in python?

如果您使用的是 Python3.x，您可以试试这个：

from datetime import datetime

item = "01/Jul/1995:00:00:01-0400"
checkdate = datetime.strptime(item,"%d/%b/%Y:%H:%M:%S%z")

print(checkdate)

结果：

1995-07-01 00:00:01-04:00

查看来自 strftime() and strptime() Behavior

的更多详细信息

Answer 2

我修正了你的日期转换。很棒的是 %f 在 Python 2.7 和 3.x.

中均受支持

from datetime import datetime

item = "01/Jul/1995:00:00:01-0400"
checkdate = datetime.strptime(item,"%d/%b/%Y:%H:%M:%S-%f")

print(checkdate)

strptime 如何解析：01/Jul/1995:00:00:01-0400

strptime how to parse : 01/Jul/1995:00:00:01-0400

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