将几个数组组合成 JavaScript 中的对象数组
Combine several arrays into an array of objects in JavaScript
假设我有三个数组,描述了一些名字、阅读的书籍数量以及这些人 [in names] 有多棒:
let names = ["Mary", "Joe", "Kenan"];
let numberOfBooks = [2, 1, 4];
let awesomenessLevel = ["pretty cool", "meh", "super-reader"];
我正在尝试使用 .reduce()
将它们组合在一起以创建一个对象数组,其中包含每个数组中的相关索引,但我失败得很惨:
let people = [
{
name: "Mary",
noOfBooks: 2,
awesomeness: "pretty cool"
},
{
name: "Joe",
noOfBooks: 1,
awesomeness: "meh"
},
{
name: "Kenan",
noOfBooks: 4,
awesomeness: "super-reader"
}
]
我也用 reduce 得到了它:
let arrFinal = [];
names.reduce(function(all, item, index) {
arrFinal.push({
name: item,
noOfBooks: numberOfBooks[index],
awesomeness: awesomenessLevel[index]
})
}, []);
使用map
在输入数组和输出数组之间创建一对一的映射。
let people = names.map(function (e, i) {
return {name:e, noOfBooks:numberOfBooks[i],awesomeness: awesomenessLevel[i]};
});
let names = ["Mary", "Joe", "Kenan"];
let numberOfBooks = [2, 1, 4];
let awesomenessLevel = ["pretty cool", "meh", "super-reader"];
let people = names.map(function (e, i) {
return {name:e, noOfBooks:numberOfBooks[i],awesomeness: awesomenessLevel[i]};
});
console.log(people);
你可以用 map
来做,像这样:
let result = names.map( (v, i) => ({
name: names[i],
noOfBooks: numberOfBooks[i],
awesomenessLevel: awesomenessLevel[i]
}));
let names = ["Mary", "Joe", "Kenan"];
let numberOfBooks = [2, 1, 4];
let awesomenessLevel = ["pretty cool", "meh", "super-reader"];
let result = names.map( (v, i) => ({
name: names[i],
noOfBooks: numberOfBooks[i],
awesomenessLevel: awesomenessLevel[i]
}));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
map
在这种情况下比 reduce
效果更好,因为 names 数组(或其他两个中的任何一个)中的元素数量) 与输出中所需的元素数相同。在这种情况下,使用 map
.
更为自然
您可以使用一种动态方法,将所有数组组合到一个对象,并将键名称用作数组中结果对象的 属性 名称
let names = ["Mary", "Joe", "Kenan"],
numberOfBooks = [2, 1, 4],
awesomenessLevel = ["pretty cool", "meh", "super-reader"],
object = { name: names, noOfBooks: numberOfBooks, awesomeness: awesomenessLevel },
result = Object.keys(object).reduce((r, k) =>
(object[k].forEach((a, i) =>
(r[i] = r[i] || {})[k] = a), r), []);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
假设我有三个数组,描述了一些名字、阅读的书籍数量以及这些人 [in names] 有多棒:
let names = ["Mary", "Joe", "Kenan"];
let numberOfBooks = [2, 1, 4];
let awesomenessLevel = ["pretty cool", "meh", "super-reader"];
我正在尝试使用 .reduce()
将它们组合在一起以创建一个对象数组,其中包含每个数组中的相关索引,但我失败得很惨:
let people = [
{
name: "Mary",
noOfBooks: 2,
awesomeness: "pretty cool"
},
{
name: "Joe",
noOfBooks: 1,
awesomeness: "meh"
},
{
name: "Kenan",
noOfBooks: 4,
awesomeness: "super-reader"
}
]
我也用 reduce 得到了它:
let arrFinal = [];
names.reduce(function(all, item, index) {
arrFinal.push({
name: item,
noOfBooks: numberOfBooks[index],
awesomeness: awesomenessLevel[index]
})
}, []);
使用map
在输入数组和输出数组之间创建一对一的映射。
let people = names.map(function (e, i) {
return {name:e, noOfBooks:numberOfBooks[i],awesomeness: awesomenessLevel[i]};
});
let names = ["Mary", "Joe", "Kenan"];
let numberOfBooks = [2, 1, 4];
let awesomenessLevel = ["pretty cool", "meh", "super-reader"];
let people = names.map(function (e, i) {
return {name:e, noOfBooks:numberOfBooks[i],awesomeness: awesomenessLevel[i]};
});
console.log(people);
你可以用 map
来做,像这样:
let result = names.map( (v, i) => ({
name: names[i],
noOfBooks: numberOfBooks[i],
awesomenessLevel: awesomenessLevel[i]
}));
let names = ["Mary", "Joe", "Kenan"];
let numberOfBooks = [2, 1, 4];
let awesomenessLevel = ["pretty cool", "meh", "super-reader"];
let result = names.map( (v, i) => ({
name: names[i],
noOfBooks: numberOfBooks[i],
awesomenessLevel: awesomenessLevel[i]
}));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
map
在这种情况下比 reduce
效果更好,因为 names 数组(或其他两个中的任何一个)中的元素数量) 与输出中所需的元素数相同。在这种情况下,使用 map
.
您可以使用一种动态方法,将所有数组组合到一个对象,并将键名称用作数组中结果对象的 属性 名称
let names = ["Mary", "Joe", "Kenan"],
numberOfBooks = [2, 1, 4],
awesomenessLevel = ["pretty cool", "meh", "super-reader"],
object = { name: names, noOfBooks: numberOfBooks, awesomeness: awesomenessLevel },
result = Object.keys(object).reduce((r, k) =>
(object[k].forEach((a, i) =>
(r[i] = r[i] || {})[k] = a), r), []);
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }