找到 xls 标签和他的孩子 python
find xls tag and his childs whith python
我在 xls 代码文件中找到特定标签并与他的孩子一起获取时遇到了一些麻烦。
例如：
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://www.w3.org/2003/05/soap-envelope" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/" xmlns:crossFunction="http://bla.bla.bla/" xmlns:simple-date-format="xalan://java.text.SimpleDateFormat" xmlns:srv="bla.bla.bla1" xmlns:xdt="http://www.w3.org/2005/02/xpath-datatypes" xmlns:date="http://exslt.org/dates-and-times" xmlns:customCoreFunction="http://bla.bla.bla2" xmlns:xalan="http://xml.apache.org/xalan" xmlns:productCoreFunction="http://bla.bla.bla" xmlns:srvesb0="http://esb.original.com.br/HistoricoComentario" xmlns:exsl="http://exslt.org/common" version="1.0" exclude-result-prefixes="xbla.bla.bla">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="no"/>
<xsl:variable name="uriTokenSeparator" select="';'"/>
<xsl:variable name="uriKeyValueSeparator" select="'='"/>
<xsl:template match="/">
<xsl:variable name="messageContext" select="."/>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soapenv:Header></soapenv:Header>
<soapenv:Body>
<xsl:element name="srvesb0:getHistory">
<xsl:if test="((/soap:Envelope/soap:Body/*/note[@name='note']/catchId) and ((/soap:Envelope/soap:Body/*/note[@name='note']/catchId!='') or (/soap:Envelope/soap:Body/*/note[@name='note']/catchId/@*)))">
<xsl:element name="srvesb0:idCapture">
<xsl:value-of select="/soap:Envelope/soap:Body/*/note[@name='note']/catchId"/>
</xsl:element>
</xsl:if>
</xsl:element>
</soapenv:Body>
</soapenv:Envelope>
</xsl:template>
</xsl:stylesheet>
我只需要获取 'Body' 标签内的代码：
<soapenv:Body>
<xsl:element name="srvesb0:getHistory">
<xsl:if test="((/soap:Envelope/soap:Body/*/note[@name='note']/catchId) and ((/soap:Envelope/soap:Body/*/note[@name='note']/catchId!='') or (/soap:Envelope/soap:Body/*/note[@name='note']/catchId/@*)))">
<xsl:element name="srvesb0:idCapture">
<xsl:value-of select="/soap:Envelope/soap:Body/*/note[@name='note']/catchId"/>
</xsl:element>
</xsl:if>
</xsl:element>
</soapenv:Body>
然后，逐个元素迭代并获取它的属性。
但我使用的任何搜索代码都有效
.xpath
.iter
.find
如果我迭代 .getroot() 结果出现：
import lxml.etree as XT
xslt = XT.parse('transformation.xsl')
rootxslt = xslt.getroot()
for child in rootxslt:
child.tag = child.tag.split('}', 1)[1] # strip all namespaces
print child.tag, child.attrib, child.text
for child2 in child:
child2.tag = child2.tag.split('}', 1)[1] # strip all namespaces
print child2.tag, child2.attrib, child2.text
for child3 in child2:
child3.tag = child3.tag.split('}', 1)[1] # strip all namespaces
print child3.tag, child3.text, child3.text
for child4 in child3:
child4.tag = child4.tag.split('}', 1)[1] # strip all namespaces
print child4.tag, child4.text, child4.text
for child5 in child4:
child5.tag = child5.tag.split('}', 1)[1] # strip all namespaces
print child5.tag, child5.text, child5.text
但是如果尝试迭代特定标签，会出现任何结果：
import lxml.etree as XT
xslt = XT.parse('transformation.xsl')
rootxslt = xslt.getroot()
for child in rootxslt.findall("Body"):
child.tag = child.tag.split('}', 1)[1] # strip all namespaces
print child.tag, child.attrib, child.text
for child2 in child:
child2.tag = child2.tag.split('}', 1)[1] # strip all namespaces
print child2.tag, child2.attrib, child2.text
for child3 in child2:
child3.tag = child3.tag.split('}', 1)[1] # strip all namespaces
print child3.tag, child3.text, child3.text
for child4 in child3:
child4.tag = child4.tag.split('}', 1)[1] # strip all namespaces
print child4.tag, child4.text, child4.text
for child5 in child4:
child5.tag = child5.tag.split('}', 1)[1] # strip all namespaces
print child5.tag, child5.text, child5.text
有人知道如何从 'Body' 标签中获取树吗？
谢谢
您可以使用 xpath 方法来完成此操作。
>>> import lxml.etree as XT
>>> xslt = XT.parse('c:/scratch/sample.xml')
>>> xslt.xpath('.//soapenv:Body', namespaces={'soapenv': 'http://schemas.xmlsoap.org/soap/envelope/'})
[<Element {http://schemas.xmlsoap.org/soap/envelope/}Body at 0x5e60c88>]
>>> theBody[0]
<Element {http://schemas.xmlsoap.org/soap/envelope/}Body at 0x5e60c88>
>>> list(theBody[0].iterdescendants())
[<Element {http://www.w3.org/1999/XSL/Transform}element at 0x5e60b08>, <Element {http://www.w3.org/1999/XSL/Transform}if at 0x5e7ea08>, <Element {http://www.w3.org/1999/XSL/Transform}element at 0x5e7ea48>, <Element {http://www.w3.org/1999/XSL/Transform}value-of at 0x5e7ea88>]
找到所需代码的容器后，如此处所示，您可以遍历容器的后代。
编辑：另一种方法。
假设：(1) 同一个命名空间适用于多种 xsl 文档，如以下代码所示。 (2) xsl:variable messageContext 将紧接在您想要的任何内容之前。
然后从查找该内容之前的 messageContext 元素开始。现在找到这个旁边的元素。最后，遍历消息内容的 body 的后代。或者你想做什么。
>>> import lxml.etree as XT
>>> xslt = XT.parse('sample.xml')
>>> sibling = xslt.xpath('.//xsl:variable[@name="messageContext"]', namespaces={'xsl': "http://www.w3.org/1999/XSL/Transform"})
<Element {http://schemas.xmlsoap.org/soap/envelope/}Envelope at 0x11912c8>
>>> envelope = sibling[0].getnext()
>>> list(envelope.iter())
[<Element {http://schemas.xmlsoap.org/soap/envelope/}Envelope at 0x11912c8>, <Element {http://schemas.xmlsoap.org/soap/envelope/}Header at 0x1191448>, <Element {http://schemas.xmlsoap.org/soap/envelope/}Body at 0x1191248>, <Element {http://www.w3.org/1999/XSL/Transform}element at 0x11910c8>, <Element {http://www.w3.org/1999/XSL/Transform}if at 0x1191488>, <Element {http://www.w3.org/1999/XSL/Transform}element at 0x11914c8>, <Element {http://www.w3.org/1999/XSL/Transform}value-of at 0x1191508>]
编辑 2：另一个，使用 BeautifulSoup。如果你使用 'xml' 作为 BeautifulSoup 的第二个参数，那么你可以很容易地解析命名空间元素，正如我刚刚从 .
中学到的那样
>>> import bs4
>>> soup = bs4.BeautifulSoup(open('sample.xml').read(), 'xml')
>>> body = soup.find_all('Body')
>>> body
[<Body>
<xsl:element name="srvesb0:getHistory">
<xsl:if test="((/soap:Envelope/soap:Body/*/note[@name='note']/catchId) and ((/soap:Envelope/soap:Body/*/note[@name='note']/catchId!='') or (/soap:Envelope/soap:Body/*/note[@name='note']/catchId/@*)))">
<xsl:element name="srvesb0:idCapture">
<xsl:value-of select="/soap:Envelope/soap:Body/*/note[@name='note']/catchId"/>
</xsl:element>
</xsl:if>
</xsl:element>
</Body>]
>>> body[0].find('value-of')
<xsl:value-of select="/soap:Envelope/soap:Body/*/note[@name='note']/catchId"/>
我在 xls 代码文件中找到特定标签并与他的孩子一起获取时遇到了一些麻烦。
例如：
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://www.w3.org/2003/05/soap-envelope" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/" xmlns:crossFunction="http://bla.bla.bla/" xmlns:simple-date-format="xalan://java.text.SimpleDateFormat" xmlns:srv="bla.bla.bla1" xmlns:xdt="http://www.w3.org/2005/02/xpath-datatypes" xmlns:date="http://exslt.org/dates-and-times" xmlns:customCoreFunction="http://bla.bla.bla2" xmlns:xalan="http://xml.apache.org/xalan" xmlns:productCoreFunction="http://bla.bla.bla" xmlns:srvesb0="http://esb.original.com.br/HistoricoComentario" xmlns:exsl="http://exslt.org/common" version="1.0" exclude-result-prefixes="xbla.bla.bla">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="no"/>
<xsl:variable name="uriTokenSeparator" select="';'"/>
<xsl:variable name="uriKeyValueSeparator" select="'='"/>
<xsl:template match="/">
<xsl:variable name="messageContext" select="."/>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soapenv:Header></soapenv:Header>
<soapenv:Body>
<xsl:element name="srvesb0:getHistory">
<xsl:if test="((/soap:Envelope/soap:Body/*/note[@name='note']/catchId) and ((/soap:Envelope/soap:Body/*/note[@name='note']/catchId!='') or (/soap:Envelope/soap:Body/*/note[@name='note']/catchId/@*)))">
<xsl:element name="srvesb0:idCapture">
<xsl:value-of select="/soap:Envelope/soap:Body/*/note[@name='note']/catchId"/>
</xsl:element>
</xsl:if>
</xsl:element>
</soapenv:Body>
</soapenv:Envelope>
</xsl:template>
</xsl:stylesheet>
我只需要获取 'Body' 标签内的代码：
<soapenv:Body>
<xsl:element name="srvesb0:getHistory">
<xsl:if test="((/soap:Envelope/soap:Body/*/note[@name='note']/catchId) and ((/soap:Envelope/soap:Body/*/note[@name='note']/catchId!='') or (/soap:Envelope/soap:Body/*/note[@name='note']/catchId/@*)))">
<xsl:element name="srvesb0:idCapture">
<xsl:value-of select="/soap:Envelope/soap:Body/*/note[@name='note']/catchId"/>
</xsl:element>
</xsl:if>
</xsl:element>
</soapenv:Body>
然后，逐个元素迭代并获取它的属性。
但我使用的任何搜索代码都有效 .xpath .iter .find
如果我迭代 .getroot() 结果出现：
import lxml.etree as XT
xslt = XT.parse('transformation.xsl')
rootxslt = xslt.getroot()
for child in rootxslt:
child.tag = child.tag.split('}', 1)[1] # strip all namespaces
print child.tag, child.attrib, child.text
for child2 in child:
child2.tag = child2.tag.split('}', 1)[1] # strip all namespaces
print child2.tag, child2.attrib, child2.text
for child3 in child2:
child3.tag = child3.tag.split('}', 1)[1] # strip all namespaces
print child3.tag, child3.text, child3.text
for child4 in child3:
child4.tag = child4.tag.split('}', 1)[1] # strip all namespaces
print child4.tag, child4.text, child4.text
for child5 in child4:
child5.tag = child5.tag.split('}', 1)[1] # strip all namespaces
print child5.tag, child5.text, child5.text
但是如果尝试迭代特定标签，会出现任何结果：
import lxml.etree as XT
xslt = XT.parse('transformation.xsl')
rootxslt = xslt.getroot()
for child in rootxslt.findall("Body"):
child.tag = child.tag.split('}', 1)[1] # strip all namespaces
print child.tag, child.attrib, child.text
for child2 in child:
child2.tag = child2.tag.split('}', 1)[1] # strip all namespaces
print child2.tag, child2.attrib, child2.text
for child3 in child2:
child3.tag = child3.tag.split('}', 1)[1] # strip all namespaces
print child3.tag, child3.text, child3.text
for child4 in child3:
child4.tag = child4.tag.split('}', 1)[1] # strip all namespaces
print child4.tag, child4.text, child4.text
for child5 in child4:
child5.tag = child5.tag.split('}', 1)[1] # strip all namespaces
print child5.tag, child5.text, child5.text
有人知道如何从 'Body' 标签中获取树吗？
谢谢
您可以使用 xpath 方法来完成此操作。
>>> import lxml.etree as XT
>>> xslt = XT.parse('c:/scratch/sample.xml')
>>> xslt.xpath('.//soapenv:Body', namespaces={'soapenv': 'http://schemas.xmlsoap.org/soap/envelope/'})
[<Element {http://schemas.xmlsoap.org/soap/envelope/}Body at 0x5e60c88>]
>>> theBody[0]
<Element {http://schemas.xmlsoap.org/soap/envelope/}Body at 0x5e60c88>
>>> list(theBody[0].iterdescendants())
[<Element {http://www.w3.org/1999/XSL/Transform}element at 0x5e60b08>, <Element {http://www.w3.org/1999/XSL/Transform}if at 0x5e7ea08>, <Element {http://www.w3.org/1999/XSL/Transform}element at 0x5e7ea48>, <Element {http://www.w3.org/1999/XSL/Transform}value-of at 0x5e7ea88>]
找到所需代码的容器后，如此处所示，您可以遍历容器的后代。
编辑：另一种方法。
假设：(1) 同一个命名空间适用于多种 xsl 文档，如以下代码所示。 (2) xsl:variable messageContext 将紧接在您想要的任何内容之前。
然后从查找该内容之前的 messageContext 元素开始。现在找到这个旁边的元素。最后，遍历消息内容的 body 的后代。或者你想做什么。
>>> import lxml.etree as XT
>>> xslt = XT.parse('sample.xml')
>>> sibling = xslt.xpath('.//xsl:variable[@name="messageContext"]', namespaces={'xsl': "http://www.w3.org/1999/XSL/Transform"})
<Element {http://schemas.xmlsoap.org/soap/envelope/}Envelope at 0x11912c8>
>>> envelope = sibling[0].getnext()
>>> list(envelope.iter())
[<Element {http://schemas.xmlsoap.org/soap/envelope/}Envelope at 0x11912c8>, <Element {http://schemas.xmlsoap.org/soap/envelope/}Header at 0x1191448>, <Element {http://schemas.xmlsoap.org/soap/envelope/}Body at 0x1191248>, <Element {http://www.w3.org/1999/XSL/Transform}element at 0x11910c8>, <Element {http://www.w3.org/1999/XSL/Transform}if at 0x1191488>, <Element {http://www.w3.org/1999/XSL/Transform}element at 0x11914c8>, <Element {http://www.w3.org/1999/XSL/Transform}value-of at 0x1191508>]
编辑 2：另一个，使用 BeautifulSoup。如果你使用 'xml' 作为 BeautifulSoup 的第二个参数，那么你可以很容易地解析命名空间元素，正如我刚刚从 .
>>> import bs4
>>> soup = bs4.BeautifulSoup(open('sample.xml').read(), 'xml')
>>> body = soup.find_all('Body')
>>> body
[<Body>
<xsl:element name="srvesb0:getHistory">
<xsl:if test="((/soap:Envelope/soap:Body/*/note[@name='note']/catchId) and ((/soap:Envelope/soap:Body/*/note[@name='note']/catchId!='') or (/soap:Envelope/soap:Body/*/note[@name='note']/catchId/@*)))">
<xsl:element name="srvesb0:idCapture">
<xsl:value-of select="/soap:Envelope/soap:Body/*/note[@name='note']/catchId"/>
</xsl:element>
</xsl:if>
</xsl:element>
</Body>]
>>> body[0].find('value-of')
<xsl:value-of select="/soap:Envelope/soap:Body/*/note[@name='note']/catchId"/>