从 distutils 设置调用中获取发行版
Get the distro from a distutils setup call
我想对一些 Python 扩展进行单元测试。为了实现这一点,我在脚本中 运行ning setup()
:
from distutils.core import setup, Extension
import os
DIR = os.path.dirname(__file__)
def call_setup():
module1 = Extension('callbacks',
sources = [os.path.join(DIR, 'callbacks.c')])
setup(
script_name = 'setup.py',
script_args = ['build'],
name = 'PackageName',
ext_modules = [module1])
为了避免在测试目录中留下垃圾,我想在测试后清理构建 运行。我想在单元测试中 运行 distutils.command.clean.clean()
tearDown()
。如何获取必须作为参数传递给 clean()
的发行版的 dist
对象?
谢谢
看起来你对 setup()
的调用应该 return a Distribution
instance.
See the setup()
function for a list of keyword arguments accepted by the Distribution
constructor. setup()
creates a Distribution instance.
我想对一些 Python 扩展进行单元测试。为了实现这一点,我在脚本中 运行ning setup()
:
from distutils.core import setup, Extension
import os
DIR = os.path.dirname(__file__)
def call_setup():
module1 = Extension('callbacks',
sources = [os.path.join(DIR, 'callbacks.c')])
setup(
script_name = 'setup.py',
script_args = ['build'],
name = 'PackageName',
ext_modules = [module1])
为了避免在测试目录中留下垃圾,我想在测试后清理构建 运行。我想在单元测试中 运行 distutils.command.clean.clean()
tearDown()
。如何获取必须作为参数传递给 clean()
的发行版的 dist
对象?
谢谢
看起来你对 setup()
的调用应该 return a Distribution
instance.
See the
setup()
function for a list of keyword arguments accepted by theDistribution
constructor.setup()
creates a Distribution instance.