每个用户只有 SQL select 行具有最大日期
SQL only select rows with max date within each user
SQL 初学者。我有一个用户进行的简单测试,每一行都是他们一个问题的答案。他们被允许每天参加一次考试,所以有些人在另一天参加第二次考试,因此会有很多行具有不同的考试日期。我基本上想做的是获取每个用户的最新分数。
这是我的数据(table 名称是 dumdum):
+----------+----------------+----------+------------------+
| USERNAME | CORRECT_ANSWER | RESPONSE | DATE_TAKEN |
+----------+----------------+----------+------------------+
| matt | 1 | 1 | 3/23/15 1:04:26 |
| matt | 2 | 2 | 3/23/15 1:04:28 |
| matt | 3 | 3 | 3/23/15 1:04:23 |
| david | 1 | 3 | 3/20/15 1:04:25 |
| david | 2 | 2 | 3/20/15 1:04:28 |
| david | 3 | 1 | 3/20/15 1:04:30 |
| david | 1 | 1 | 3/21/15 11:03:14 |
| david | 2 | 3 | 3/21/15 11:03:17 |
| david | 3 | 2 | 3/21/15 11:03:19 |
| chris | 1 | 2 | 3/17/15 12:45:52 |
| chris | 2 | 2 | 3/17/15 12:45:56 |
| chris | 3 | 3 | 3/17/15 12:45:59 |
| peter | 1 | 1 | 3/19/15 2:45:33 |
| peter | 2 | 3 | 3/19/15 2:45:35 |
| peter | 3 | 2 | 3/19/15 2:45:38 |
| peter | 1 | 1 | 3/20/15 12:32:04 |
| peter | 2 | 2 | 3/20/15 12:32:05 |
| peter | 3 | 3 | 3/20/15 12:32:05 |
+----------+----------------+----------+------------------+
以及我最终想要得到的...
+----------+------------------+-------+
| USERNAME | MOST_RECENT_TEST | SCORE |
+----------+------------------+-------+
| matt | 3/23/2015 | 100 |
| david | 3/21/2015 | 33 |
| chris | 3/17/2015 | 67 |
| peter | 3/20/2015 | 100 |
+----------+------------------+-------+
我 运行 遇到了一些麻烦,因为我需要白天去,而不是 day/time,所以我不得不做一个奇怪的动作,我去角色并回到约会.. . 这就是我目前所拥有的,但我无法弄清楚如何只使用最近一次测试的分数(现在它考虑了每一次测试的所有分数)...
SELECT username, to_date(substr(max(test_date),1,9),'dd-MON-yy') as most_recent_test, round((sum(case when response=correct_answer then 1 end)/3)*100,0) as score
FROM dumdum group by username
如有任何帮助,我们将不胜感激!谢谢!
这个问题有多种解决方案,这个解决方案使用 WITH 子句和 RANK 函数。
它也使用 TRUNC
函数而不是 to_date(substr(
with mxDate as
(SELECT USERNAME,
TRUNC(DATE_TAKEN) as MOST_RECENT_TEST,
CASE WHEN CORRECT_ANSWER = RESPONSE THEN 1 else 0 END as SCORE,
RANK () OVER (PARTITION BY USERNAME
ORDER BY TRUNC(DATE_TAKEN) DESC) Rk
FROM dumdum)
SELECT
USERNAME,
MOST_RECENT_TEST,
SUM(SCORE)/3 * 100
FROM
mxDate
WHERE
rk = 1
GROUP BY
USERNAME,
MOST_RECENT_TEST
SQL 初学者。我有一个用户进行的简单测试,每一行都是他们一个问题的答案。他们被允许每天参加一次考试,所以有些人在另一天参加第二次考试,因此会有很多行具有不同的考试日期。我基本上想做的是获取每个用户的最新分数。
这是我的数据(table 名称是 dumdum):
+----------+----------------+----------+------------------+
| USERNAME | CORRECT_ANSWER | RESPONSE | DATE_TAKEN |
+----------+----------------+----------+------------------+
| matt | 1 | 1 | 3/23/15 1:04:26 |
| matt | 2 | 2 | 3/23/15 1:04:28 |
| matt | 3 | 3 | 3/23/15 1:04:23 |
| david | 1 | 3 | 3/20/15 1:04:25 |
| david | 2 | 2 | 3/20/15 1:04:28 |
| david | 3 | 1 | 3/20/15 1:04:30 |
| david | 1 | 1 | 3/21/15 11:03:14 |
| david | 2 | 3 | 3/21/15 11:03:17 |
| david | 3 | 2 | 3/21/15 11:03:19 |
| chris | 1 | 2 | 3/17/15 12:45:52 |
| chris | 2 | 2 | 3/17/15 12:45:56 |
| chris | 3 | 3 | 3/17/15 12:45:59 |
| peter | 1 | 1 | 3/19/15 2:45:33 |
| peter | 2 | 3 | 3/19/15 2:45:35 |
| peter | 3 | 2 | 3/19/15 2:45:38 |
| peter | 1 | 1 | 3/20/15 12:32:04 |
| peter | 2 | 2 | 3/20/15 12:32:05 |
| peter | 3 | 3 | 3/20/15 12:32:05 |
+----------+----------------+----------+------------------+
以及我最终想要得到的...
+----------+------------------+-------+
| USERNAME | MOST_RECENT_TEST | SCORE |
+----------+------------------+-------+
| matt | 3/23/2015 | 100 |
| david | 3/21/2015 | 33 |
| chris | 3/17/2015 | 67 |
| peter | 3/20/2015 | 100 |
+----------+------------------+-------+
我 运行 遇到了一些麻烦,因为我需要白天去,而不是 day/time,所以我不得不做一个奇怪的动作,我去角色并回到约会.. . 这就是我目前所拥有的,但我无法弄清楚如何只使用最近一次测试的分数(现在它考虑了每一次测试的所有分数)...
SELECT username, to_date(substr(max(test_date),1,9),'dd-MON-yy') as most_recent_test, round((sum(case when response=correct_answer then 1 end)/3)*100,0) as score
FROM dumdum group by username
如有任何帮助,我们将不胜感激!谢谢!
这个问题有多种解决方案,这个解决方案使用 WITH 子句和 RANK 函数。
它也使用 TRUNC
函数而不是 to_date(substr(
with mxDate as
(SELECT USERNAME,
TRUNC(DATE_TAKEN) as MOST_RECENT_TEST,
CASE WHEN CORRECT_ANSWER = RESPONSE THEN 1 else 0 END as SCORE,
RANK () OVER (PARTITION BY USERNAME
ORDER BY TRUNC(DATE_TAKEN) DESC) Rk
FROM dumdum)
SELECT
USERNAME,
MOST_RECENT_TEST,
SUM(SCORE)/3 * 100
FROM
mxDate
WHERE
rk = 1
GROUP BY
USERNAME,
MOST_RECENT_TEST