显示所有签名的短号码的程序

Question

*编辑：我错误地删除了我写的关于使用 short & char 在现代编程中有点过时/效率不高的评论。这个只是为了练习基本的东西。**

此程序从值 0 开始的无符号短整型 "space/world" 中的等价物开始创建并打印一系列有符号短整型值。

**示例：在 short 为 16 位的机器上：
无符号短：0 1 2 .... 65535
=> 签名短：0 1 2 ... 32766 -32767 -32766 -32765 ... -2 -1

#include <stdio.h>
#include <stdlib.h>
#include <limits.h>

//Initialize memory pointed by p with values 0 1 ... n
//Assumption : the value of n can be converted to 
//             short int (without over/under-flow)
unsigned int initArr (short int *p, unsigned int n);

int main (void)
{
  const unsigned int lastNumInSeq = USHRT_MAX;
  short *p_arr = (short *) malloc ( (lastNumInSeq + 1) * sizeof (short));
  short int lastValSet = initArr (p_arr, lastNumInSeq); //returns the "max" val written

//  for (unsigned i = 0; i < numOfElem; i++)
//      printf ("[%d]=%d \n", i, (*(p_arr + i)));

  printf ("lastValSet = %d *(p_arr + lastNumInSeq) = %d  ",
           lastValSet,*(p_arr + lastNumInSeq ));

  return 0;
}

unsigned int initArr (short *p, unsigned int n)
{
  unsigned int offset,index = 0;

  while (index <= n){
      offset = index;
      *(p + offset) = ++index -1 ;
  }

  return offset;

Answer 1

还需要一些其他清理工作。

函数签名应该从

    short initArr (short *p, unsigned int n);

至

    unsigned int initArr (short *p, unsigned int n);

变量 'lastValSet' 应将其类型更改为 unsigned int。

这条评论也很混乱：

    //Assumption : the value of n can be converted to 
    //             short int (without over/under-flow)

应该是这样的：

    //Assumption : the value of n which is of type int can be converted to 
    //             short int (without over/under-flow) up to 32767 which is the 
    //             max value for a variable of short type.

显示所有签名的短号码的程序

Program which displays the all signed short numbers

c

ansi-c