用于计算普通成员的 MDX - EXISTS 替代方案
MDX to count common members - EXISTS alternative
让我用[Adventure Works]立方体的例子来描述这个问题。
以下 MDX returns 计数为 17473
SELECT NON EMPTY { [Measures].[Internet Order Count] } ON COLUMNS,
[Internet Sales Order Details].[Sales Order Number] on ROWS
FROM [Adventure Works])
WHERE ( [Sales Reason].[Sales Reason].&[1] -- price
和以下 returns 计数 3515
SELECT NON EMPTY { [Measures].[Internet Order Count] } ON COLUMNS ,
[Internet Sales Order Details].[Sales Order Number] on ROWS
FROM [Adventure Works]
WHERE ( [Sales Reason].[Sales Reason].&[2]) -- on promotion
我想统计[Sales Reason].&1和[Sales Reason].&[2]
中常见的[Sales Order Number]
SQL 等价于:
select count(distinct f.SalesOrderNumber)
from FactInternetSales f
join FactInternetSalesReason fs
on f.SalesOrderNumber = fs.SalesOrderNumber and f.SalesOrderLineNumber = fs.SalesOrderLineNumber
where fs.SalesReasonKey = 1 and fs.SalesOrderNumber in
(select SalesOrderNumber from FactInternetSalesReason fs1 where fs1.SalesReasonKey = 2)
-- sales reason 1 = 17473
-- sales reason 2 = 3515
-- common 1689
我使用以下 mdx 得到了共同计数:
WITH MEMBER [Measures].[common] AS count
( exists ( exists ([Internet Sales Order Details].[Sales Order Number].[Sales Order Number].Members,
[Sales Reason].[Sales Reason].&[1],"Internet Orders"
),
[Sales Reason].[Sales Reason].&[2],"Internet Orders"
)
)
SELECT NON EMPTY [Measures].[common] ON COLUMNS
FROM [Adventure Works]
-- 1689
但是使用 EXISTS 对我的要求来说相当慢。请提出替代方案。
另请参阅相关主题here
谢谢
请尝试将这两个原因作为一个集合添加到 WHERE
子句中:
SELECT
NON EMPTY
{[Measures].[Internet Order Count]} ON COLUMNS
,[Internet Sales Order Details].[Sales Order Number] ON ROWS
FROM [Adventure Works]
WHERE
{
[Sales Reason].[Sales Reason].&[2]
,[Sales Reason].[Sales Reason].&[1]
};
这里有一个运行速度比较快的替代方案,只看常用命令,不使用EXISTS
函数:
WITH
SET [AllOrders] AS
[Internet Sales Order Details].[Sales Order Number].[Sales Order Number].MEMBERS
SET [OrdersIntersection] AS
Intersect
(
NonEmpty
(
[AllOrders]
,{
(
[Sales Reason].[Sales Reason].&[1]
,[Measures].[Internet Order Count]
)
}
)
,NonEmpty
(
[AllOrders]
,{
(
[Sales Reason].[Sales Reason].&[2]
,[Measures].[Internet Order Count]
)
}
)
)
MEMBER [Measures].[commonCount] AS
[OrdersIntersection].Count
SELECT
//NON EMPTY //<<not needed
[Measures].[commonCount] ON COLUMNS
FROM [Adventure Works];
让我用[Adventure Works]立方体的例子来描述这个问题。
以下 MDX returns 计数为 17473
SELECT NON EMPTY { [Measures].[Internet Order Count] } ON COLUMNS,
[Internet Sales Order Details].[Sales Order Number] on ROWS
FROM [Adventure Works])
WHERE ( [Sales Reason].[Sales Reason].&[1] -- price
和以下 returns 计数 3515
SELECT NON EMPTY { [Measures].[Internet Order Count] } ON COLUMNS ,
[Internet Sales Order Details].[Sales Order Number] on ROWS
FROM [Adventure Works]
WHERE ( [Sales Reason].[Sales Reason].&[2]) -- on promotion
我想统计[Sales Reason].&1和[Sales Reason].&[2]
中常见的[Sales Order Number]SQL 等价于:
select count(distinct f.SalesOrderNumber)
from FactInternetSales f
join FactInternetSalesReason fs
on f.SalesOrderNumber = fs.SalesOrderNumber and f.SalesOrderLineNumber = fs.SalesOrderLineNumber
where fs.SalesReasonKey = 1 and fs.SalesOrderNumber in
(select SalesOrderNumber from FactInternetSalesReason fs1 where fs1.SalesReasonKey = 2)
-- sales reason 1 = 17473
-- sales reason 2 = 3515
-- common 1689
我使用以下 mdx 得到了共同计数:
WITH MEMBER [Measures].[common] AS count
( exists ( exists ([Internet Sales Order Details].[Sales Order Number].[Sales Order Number].Members,
[Sales Reason].[Sales Reason].&[1],"Internet Orders"
),
[Sales Reason].[Sales Reason].&[2],"Internet Orders"
)
)
SELECT NON EMPTY [Measures].[common] ON COLUMNS
FROM [Adventure Works]
-- 1689
但是使用 EXISTS 对我的要求来说相当慢。请提出替代方案。
另请参阅相关主题here
谢谢
请尝试将这两个原因作为一个集合添加到 WHERE
子句中:
SELECT
NON EMPTY
{[Measures].[Internet Order Count]} ON COLUMNS
,[Internet Sales Order Details].[Sales Order Number] ON ROWS
FROM [Adventure Works]
WHERE
{
[Sales Reason].[Sales Reason].&[2]
,[Sales Reason].[Sales Reason].&[1]
};
这里有一个运行速度比较快的替代方案,只看常用命令,不使用EXISTS
函数:
WITH
SET [AllOrders] AS
[Internet Sales Order Details].[Sales Order Number].[Sales Order Number].MEMBERS
SET [OrdersIntersection] AS
Intersect
(
NonEmpty
(
[AllOrders]
,{
(
[Sales Reason].[Sales Reason].&[1]
,[Measures].[Internet Order Count]
)
}
)
,NonEmpty
(
[AllOrders]
,{
(
[Sales Reason].[Sales Reason].&[2]
,[Measures].[Internet Order Count]
)
}
)
)
MEMBER [Measures].[commonCount] AS
[OrdersIntersection].Count
SELECT
//NON EMPTY //<<not needed
[Measures].[commonCount] ON COLUMNS
FROM [Adventure Works];