如何解决Hibernate "ERROR o.h.e.jdbc.spi.SqlExceptionHelper - Duplicate entry "异常

Question

我测试解决这个问题已经2天了，但没有任何效果。我在双向关系中暗示了这些实体。

@Entity
@Table( name = "T_user" )
public class T_user implements Serializable {
   @Id
   @GeneratedValue( strategy = GenerationType.IDENTITY )
   private Long               id_user;

   @OneToOne( targetEntity = T_infosProfile.class, mappedBy = "user", fetch = FetchType.LAZY, orphanRemoval = true )
   private T_infosProfile     infosProfile;

   public void setInfosProfile( T_infosProfile infosProfile ) {
    this.infosProfile = infosProfile;
   }
}

和

@Entity
@Table( name = "T_infosProfile" )
public class T_infosProfile {

   @Id
   @GeneratedValue( strategy = GenerationType.IDENTITY )
   private Long       id_infos;

   @OneToOne( targetEntity = T_user.class, fetch = FetchType.LAZY )
   @JoinColumn( name = "id_user", unique = true, nullable = false )
   private T_user user;

     @Column( name = "pourcentage_completion", length = 3, updatable = true, unique = false )
     private Integer    pourcentageCompletion;

     @Column( name = "infos_identite", nullable = false, updatable = true, length = 1, columnDefinition = "TINYINT(1)" )
     private Boolean    infosIdentiteCompleted;

     @Column( name = "infos_coordonnees", nullable = false, updatable = true, length = 1, columnDefinition = "TINYINT(1)" )
     private Boolean    infosCoordonneesCompleted;

     @Column( name = "infos_bancaires", nullable = false, updatable = true, length = 1, columnDefinition = "TINYINT(1)" )
     private Boolean    infosBancaireCompleted;

     @Column( name = "infos_chicowa", nullable = false, updatable = true, length = 1, columnDefinition = "TINYINT(1)" )
     private Boolean    infosCompleted;

   //the setter method
   public void setUser( T_user user) {
      this.user = user;
      this.infosIdentiteCompleted = true;
      this.pourcentageCompletion = 0;
      this.infosCoordonneesCompleted = this.user.getInfosCoordonnees() == null ? false : true;
      this.infosBancaireCompleted = this.user.getInfosBancaire() == null ? false : true;
      this.infosCompleted = this.user.getInfosCompleted() == null ? false : true;

      if ( this.infosCoordonneesCompleted == true ) {
        this.pourcentageCompletion = 50;
    }
      if ( this.infosBancaireCompleted == true && this.pourcentageCompletion == 50 ) {
        this.pourcentageCompletion = 75;
    }
      if ( this.infosChicowaCompleted == true && this.pourcentageCompletion == 75 ) {
        this.pourcentageCompletion = 100;
    }
  }
}

我也有这个方法用来更新用户的infosProfile :

@Service
public class UIServiceImpl implements UIService {

  @Autowired
  private TinfosProfileRepository   infosProfileRepository;

  @Override
  public T_infosProfile saveInfosPorfile( T_user connectedUser ){
    T_infosProfile infosProfile = connectedUser.getInfosProfile();
    infosProfile.setUser( connectedUser );
    connectedUser.setInfosProfile( infosProfile );
    try {
        return infosProfileRepository.save( infosProfile );
    } catch ( Exception e ) {
        throw new ExceptionsDAO( e.getMessage() );
    }
}

但是当我调用这个方法时，它适用于一种情况，但对于另一种情况，我遇到了这个异常：

10-04-2017 16:27:43 [http-nio-8080-exec-3] WARN  o.h.e.jdbc.spi.SqlExceptionHelper - SQL Error: 1062, SQLState: 23000
10-04-2017 16:27:43 [http-nio-8080-exec-3] ERROR  o.h.e.jdbc.spi.SqlExceptionHelper - Duplicate entry '8' for key 'UK_bkariaocmnn2rlh477hvoqkyf'

我只想更新当前用户的infosProfile 属性。它工作正常的情况是当只有一个 infosProfile 的属性被更新但是当我同时更新 2 个属性并尝试 saveInfosProfile() 时，会引发异常。

请帮忙。

Answer 1

查看错误消息，它不言自明，因为它说值 8 已经存在于该列中。它抛出该错误，因为您在该特定列

上定义了 UNIQUE CONSTRAINT

Duplicate entry '8' for key 'UK_bkariaocmnn2rlh477hvoqkyf'

附加：查看您的约束名称UK_bkariaocmnn2rlh477hvoqkyf。如果您在创建约束时没有命名约束，就会发生这种情况。

Answer 2

好吧，在浪费了 4 天之后，我找到了一个似乎有效的解决方案。这是我的解决方案：

@Override
public T_infosProfile saveInfosPorfile( T_user connectedUser ){
  T_infosProfile infosProfile = infosProfileRepository.findByUser(connectedUser); // I had to load by the user before saving it.
  infosProfile.setUser( connectedUser );
  connectedUser.setInfosProfile( infosProfile );
  try {
    return infosProfileRepository.save( infosProfile );
  } catch ( Exception e ) {
    throw new ExceptionsDAO( e.getMessage() );
  }
}

对我来说这是一个奇怪的行为，因为用户与 table 中保存的用户相同。感谢休眠！

Answer 3

在我的 spring 项目中解决这个问题一段时间后，我能够使用下面的代码解决我面临的问题。

infosProfile=null; try { infosProfile = infosProfileRepository.save( infosProfile ); } catch (PersistenceException ex) { Throwable cause1 = ex.getCause(); if(!isNull(cause1)){ throw new UnsupportedOperationException(cause1.getCause().getMessage()); } throw new UnsupportedOperationException(ex.getMessage()); }

如何解决Hibernate "ERROR o.h.e.jdbc.spi.SqlExceptionHelper - Duplicate entry "异常

How to solve Hibernate "ERROR o.h.e.jdbc.spi.SqlExceptionHelper - Duplicate entry " Exception

mysql

jdbc

sqlexception

hibernate-mapping

spring-data-jpa