比较两个数组的元素 php

Question

所以我有两个数组：

$badwords = array('bad-word', 'some-racist-term', 'nasty', 'bad-language');

$inputphrases = array('this-is-sentence-with-bad-word', 'nothing-bad-here', 'more-clean-stuff', 'this-is-nasty', 'this-contains-some-racist-term', 'one-more-clean', 'clean-clean', 'contains-bad-language');

我需要将输入短语数组的元素与坏词数组进行比较，并输出包含不带坏词的短语的新数组，如下所示：

$outputarray = array('nothing-bad-here', 'more-clean-stuff','one-more-clean', 'clean-clean');

我试着用两个 foreach 循环来做这件事，但它给了我相反的结果，也就是它输出了带有坏词的短语。这是我尝试输出相反结果的代码：

function letsCompare($inputphrases, $badwords)
{
    foreach ($inputphrases as $inputphrase) {

        foreach ($badwords as $badword) {

            if (strpos(strtolower(str_replace('-', '', $inputphrase)), strtolower(str_replace('-', '', $badword))) !== false) {
                $result[] = ($inputphrase);

            }
        }
    }
return $result;
}

$result = letsCompare($inputphrases, $badwords);
print_r($result);

Answer 1

这不是一个干净的解决方案，但希望您能了解正在发生的事情。不要犹豫，要求许可。 repl.it link

$inputphrases = array('this-is-sentence-with-bad-word', 'nothing-bad-here', 'more-clean-stuff', 'this-is-nasty', 'this-contains-some-racist-term', 'one-more-clean', 'clean-clean', 'contains-bad-language');


$new_arr = array_filter($inputphrases, function($phrase) {
  $badwords = array('bad-word', 'some-racist-term', 'nasty', 'bad-language');
  $c = count($badwords);
  for($i=0; $i<$c; $i++) {
    if(strpos($phrase, $badwords[$i]) !== false){
      return false;
    }
  }
  return true;
});

print_r($new_arr);

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