简单无形 HLIST 上的模式匹配
Pattern matching on a simple Shapeless HLIST
我使用 shapeless 库编写了这个简单的代码
import shapeless.LabelledGeneric
case class Icecream(name: String, numberOfCherries: Int, inCone: Boolean)
object ShapelessRecordEx2 extends App {
val gen = LabelledGeneric[Icecream]
val hlist = gen.to(Icecream("vanilla", 2, false))
hlist match {
case h :: _ => println(h)
}
}
但甚至无法编译
Error:(12, 14) constructor cannot be instantiated to expected type;
found : scala.collection.immutable.::[B]
required: shapeless.::[String with shapeless.labelled.KeyTag[Symbol with shapeless.tag.Tagged[String("name")],String],shapeless.::[Int with shapeless.labelled.KeyTag[Symbol with shapeless.tag.Tagged[String("numberOfCherries")],Int],shapeless.::[Boolean with shapeless.labelled.KeyTag[Symbol with shapeless.tag.Tagged[String("inCone")],Boolean],shapeless.HNil]]]
case h :: _ => println(h)
如果我使用的是普通列表,这段代码就没问题。
您只需要导入,默认情况下 scala.Predef
从 scala.collection.immutable.List
导入 ::
运算符。
import shapeless.LabelledGeneric
import shapeless.::
case class Icecream(name: String, numberOfCherries: Int, inCone: Boolean)
object ShapelessRecordEx2 extends App {
val gen = LabelledGeneric[Icecream]
val hlist = gen.to(Icecream("vanilla", 2, false))
hlist match {
case h :: _ => println(h)
}
}
还有一个选项,可以导入 ListCompat._
。
import shapeless.HList.ListCompat._
object ShapelessRecordEx2 extends App {
val gen = LabelledGeneric[Icecream]
val hlist = gen.to(Icecream("vanilla", 2, false))
hlist match {
case h #: _ => println(h)
}
}
我使用 shapeless 库编写了这个简单的代码
import shapeless.LabelledGeneric
case class Icecream(name: String, numberOfCherries: Int, inCone: Boolean)
object ShapelessRecordEx2 extends App {
val gen = LabelledGeneric[Icecream]
val hlist = gen.to(Icecream("vanilla", 2, false))
hlist match {
case h :: _ => println(h)
}
}
但甚至无法编译
Error:(12, 14) constructor cannot be instantiated to expected type;
found : scala.collection.immutable.::[B]
required: shapeless.::[String with shapeless.labelled.KeyTag[Symbol with shapeless.tag.Tagged[String("name")],String],shapeless.::[Int with shapeless.labelled.KeyTag[Symbol with shapeless.tag.Tagged[String("numberOfCherries")],Int],shapeless.::[Boolean with shapeless.labelled.KeyTag[Symbol with shapeless.tag.Tagged[String("inCone")],Boolean],shapeless.HNil]]]
case h :: _ => println(h)
如果我使用的是普通列表,这段代码就没问题。
您只需要导入,默认情况下 scala.Predef
从 scala.collection.immutable.List
导入 ::
运算符。
import shapeless.LabelledGeneric
import shapeless.::
case class Icecream(name: String, numberOfCherries: Int, inCone: Boolean)
object ShapelessRecordEx2 extends App {
val gen = LabelledGeneric[Icecream]
val hlist = gen.to(Icecream("vanilla", 2, false))
hlist match {
case h :: _ => println(h)
}
}
还有一个选项,可以导入 ListCompat._
。
import shapeless.HList.ListCompat._
object ShapelessRecordEx2 extends App {
val gen = LabelledGeneric[Icecream]
val hlist = gen.to(Icecream("vanilla", 2, false))
hlist match {
case h #: _ => println(h)
}
}