创建对象时，如果值未定义，则不包含在新对象中

Question

主要是 es6/7 处理对象解构的问题。

假设我有这个示例函数：

const sample = (var1, var2) => {
  const obj = {
   one: var1
  };

  if (var2) {
    obj.two = var2;
  }

  return obj;
};

这是一种说法，"the first argument is expected, if the 2nd argument is defined add it to the object too"。

是否有更优雅的方法来实现相同的效果但使用对象解构？

Answer 1

你也可以把你的函数写成

const sample = (one, two) => two? {one, two}: {one};

Its a way of saying, "the first argument is expected, if the 2nd argument is defined add it to the object too"

与您的代码一样，请注意您作为第二个参数添加的值。除了 undefined 之外，还有更多的虚假值，您可能希望将其中一些值分配给结果。如果条件是是否定义了第二个参数，我会明确检查 undefined:

const sample = (one, two) => two !== undefined? {one, two}: {one};

When creating an object, if a value is undefined don't include in the new object