我怎样才能得到某个边缘 oracle 之间的时间

Question

我需要获取时间段之间的小时数。我的代码如下，但我没有得到我需要的结果。因为它没有显示该范围内的所有结果

SELECT
    *
FROM
    (
        SELECT DISTINCT
            TO_DATE(TO_CHAR(date_quote,'dd/MM/yy'),'dd/MM/yy') date_quote,
            TO_DATE(TO_CHAR(start_time,'dd/MM/yyyy HH24:MI:SS'),'dd/MM/yyyy HH24:MI:SS') start_time,
            TO_DATE(TO_CHAR(end_time,'dd/MM/yyyy HH24:MI:SS'),'dd/MM/yyyy HH24:MI:SS') end_time

        FROM
            quote
        WHERE 
                start_time < to_timestamp('1970/01/01 11:30:00','yyyy/MM/dd HH24:MI:SS')
            and
                end_time > to_timestamp('1970/01/01 11:15:00','yyyy/MM/dd HH24:MI:SS') 

        AND
            date_quote= TO_CHAR(TO_DATE('2017-05-01','yyyy-MM-dd'),'dd/MM/yyyy')
    )
ORDER BY
    date_quote ASC,
    start_time ASC;

我也试过 >= <= 但它也没有给我预期的结果

Answer 1

假设 date_quote、fecha_apunte_fh、start_time 和 end_time 都是 DATE 或 TIMESTAMP 列并且 start_time在 end_time 之前然后

SELECT *
FROM   (
  SELECT DISTINCT
         TRUNC( date_quote ) date_quote,
         start_time,
         end_time
  FROM   quote
  WHERE  start_time > TIMESTAMP '1970-01-01 11:15:00'
  AND    end_time   < TIMESTAMP '1970-01-01 11:30:00'
  AND    fecha_apunte_fh = DATE '2017-05-01'
)
ORDER BY
    date_quote ASC,
    start_time ASC;

Answer 2

您似乎想计算关闭任务所花费的总时间。所以你可以使用

SELECT *
FROM
  (SELECT 
    TO_CHAR(TO_DATE(TO_CHAR(end_time,'dd/MM/yyyy HH24:MI:SS'),'dd/MM/yyyy HH24:MI:SS') - TO_DATE(TO_CHAR(start_time,'dd/MM/yyyy HH24:MI:SS'),'dd/MM/yyyy HH24:MI:SS'),'HH24:MI:SS') total_time_taken
  FROM quote
  WHERE start_time < to_timestamp('1970/01/01 11:30:00','yyyy/MM/dd HH24:MI:SS')
  AND end_time     > to_timestamp('1970/01/01 11:15:00','yyyy/MM/dd HH24:MI:SS')--- kinldy check your condition as end time is less then task start time
  AND date_quote   = TO_CHAR(TO_DATE('2017-05-01','yyyy-MM-dd'),'dd/MM/yyyy')
  )
ORDER BY date_quote ASC,
  start_time ASC;

我怎样才能得到某个边缘 oracle 之间的时间

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