为什么创建 NSDecimalNumber 会崩溃？

Question

我正在从云服务下载一些值作为 JSON 对象并将它们分配给 NSString 对象，如下所示

NSString *price = [orpObjectDict objectForKey:@"price"];
NSString *qty = [orpObjectDict objectForKey:@"qty"];

我的调试输出显示两个字符串的值如下

NSLog(@"price: %@ <--> qty: %@", price, qty);

2017-04-17 16:29:05.665043 NWMobileTill[1490:730225] price: 6.95 <--> qty: 1

但是下面使用这些 NSString 创建 NSDecimalNumber 失败了

NSDecimalNumber *priceNumber = [NSDecimalNumber decimalNumberWithString:price];
NSDecimalNumber *qtyNumber = [NSDecimalNumber decimalNumberWithString:qty];

017-04-17 16:29:05.665886 NWMobileTill[1490:730225] -[__NSCFNumber length]: unrecognized selector sent to instance 0x174226240
2017-04-17 16:29:05.668080 NWMobileTill[1490:730225] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[__NSCFNumber length]: unrecognized selector sent to instance 0x174226240'
*** First throw call stack:
(0x1926fd1b8 0x19113455c 0x192704268 0x192701270 0x1925fa80c 0x19323658c 0x1932340f0 0x193234754 0x1000d9078 0x192cff1e8 0x192d17120 0x1931ebfb0 0x193130aa8 0x1931210a4 0x1931ee35c 0x1006c5218 0x1006d2aec 0x1006c8ce0 0x1006d4e2c 0x1006d4b78 0x19178f2a0 0x19178ed8c)
libc++abi.dylib: terminating with uncaught exception of type NSException

为什么这个简单的创建会崩溃？

Answer 1

您可以使用 NSDecimalNumber 通过键直接检索您的对象：

NSDictionary*orpObjectDict = @{
                               @"price" : @(5.4),
                               @"qty" : @(2)
                               };
NSString *price = [orpObjectDict objectForKey:@"price"];
NSLog(@"string price %@", price);

NSString *qty = [orpObjectDict objectForKey:@"qty"];
NSLog(@"string qty %@", qty);

NSDecimalNumber*dPrice = [orpObjectDict objectForKey:@"price"];
NSLog(@"decimal price %@", dPrice);

NSDecimalNumber *dqty = [orpObjectDict objectForKey:@"qty"];
NSLog(@"decimal quantity %@", dqty);

输出是：

2017-04-17 10:46:12.932 test[2836:50653] string price 5.4
2017-04-17 10:46:12.932 test[2836:50653] string qty 2
2017-04-17 10:46:12.933 test[2836:50653] decimal price 5.4
2017-04-17 10:46:12.933 test[2836:50653] decimal quantity 2

您始终可以使用 isKindOfClass 或 isMemberOfClass 检查 return 对象类型，后者更具限制性。

根据经验，在分配之前确保字典包含键及其不是 nil 的值：

id value = dictionary[key];
if (value) {...}

或为了更好的检查：

if (value && value != [NSNull null]) {...}

编辑

我认为 Objective C 类型管理比 Swift 弱。无论如何使用 [NSDecimalNumber alloc] initWithString: 方法为您提供正确的实例。

NSDictionary*orpObjectDict = @{
                               @"price" : @"5.4",
                               @"qty" : @(2)
                               };
NSString* price = [orpObjectDict objectForKey:@"price"];
NSLog(@"string price %@", price);

NSDecimalNumber*decimalPrice = [[NSDecimalNumber alloc] initWithString:price];
if ([decimalPrice isMemberOfClass:NSDecimalNumber.class]) {
    NSLog(@"dqty is a NSDecimalNumber");
}

Answer 2

错误信息

[__NSCFNumber length]: unrecognized selector sent to instance 0x174226240

非常清楚：它表明键 price 的对象是一个 NSNumber 对象。

因此您必须从 NSNumber:

创建一个 NSDecimalNumber

NSNumber *price = orpObjectDict[@"price"];
NSDecimalNumber *priceNumber = [NSDecimalNumber decimalNumberWithDecimal:price.decimalValue];

Answer 3

您正在获取 Number 并且您正在将代码编写为字符串

请按字符串格式写成此代码

 NSString *price = [NSString stringWithFormat:@"%@", orpObjectDict objectForKey:@"price"];
 NSString *qty = [ [NSString stringWithFormat:@"%@",orpObjectDict objectForKey:@"qty"];

或简单地检查

if [price isKindOfClass:[NSString class]]
{  // It is string
}
else if [price isKindOfClass:[NSNumber class]]
{
  // It is number
}

为什么创建 NSDecimalNumber 会崩溃？

Why does this Creation of NSDecimalNumber crash?

objective-c

nsdecimalnumber

ios