我的按钮 "close" 没有关闭而是隐藏了页面

Question

大家好， 我在 closeListener 中的按钮（关闭）（在我的 java 代码中）。当我按下这个按钮（关闭）时，我正确地返回到我的第一页，但它没有正确关闭我的租借页面（第二页），我的第二页在我的第一页下方保持打开状态（隐藏在第一页后面），怎么能我为正确关闭第二页（出租）做了什么？

package albencreation.realestateapplication;

import android.content.Intent;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;

public class Rent extends AppCompatActivity {

    EditText price = null;
    EditText profit = null;
    TextView result = null;
    Button envoyer = null;
    Button close = null;
    Button info = null;
    Button clear = null;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.rent);

        price = (EditText) findViewById(R.id.price);
        profit = (EditText) findViewById(R.id.profit);
        result = (TextView) findViewById(R.id.result);
        envoyer = (Button) findViewById(R.id.buttcalculate);
        close = (Button) findViewById(R.id.buttclose);
        info = (Button) findViewById(R.id.buttinfo);
        clear = (Button) findViewById(R.id.buttclear);

        envoyer.setOnClickListener(envoyerListener);
        close.setOnClickListener(closeListener);
        info.setOnClickListener(infoListener);
        clear.setOnClickListener(clearListener);
    }

    private OnClickListener envoyerListener = new OnClickListener() {
        @Override
        public void onClick(View v) {
            String p = price.getText().toString();
            String o = profit.getText().toString();

            float pValue;
            if (p.isEmpty()) {
                pValue = 0;
            } else {
                pValue = Float.valueOf(p);
            }
            float oValue;
            if (o.isEmpty()) {
                oValue = 0;
            } else {
                oValue = Float.valueOf(o);
            }

            float resultat = oValue * pValue / 100;
            result.setText("the rent is " + String.valueOf(resultat) + " currency");
        }
    };

    private OnClickListener closeListener = new OnClickListener() {
        @Override
        public void onClick(View v) {
            Intent jumpage = new Intent(Rent.this, MainActivity.class);
            startActivity(jumpage);
        }
    };

    private OnClickListener infoListener = new OnClickListener() {
        @Override
        public void onClick(View v) {
            Intent jumpage = new Intent(Rent.this, Inforent.class);
            startActivity(jumpage);
        }
    };

    private OnClickListener clearListener = new OnClickListener() {
        @Override
        public void onClick(View v) {
            price.getText().clear();
            profit.getText().clear();
            String defaut = "result rent";
            result.setText(defaut);
        }
    };

}

Answer 1

您可以调用 finish() 方法来永久完成您的 activity:

private OnClickListener closeListener = new OnClickListener() {
        @Override
        public void onClick(View v) {
            Intent jumpage = new Intent(Rent.this, MainActivity.class);
            startActivity(jumpage);
            Rent.this.finish();
        }
    };

Answer 2

而不是这个

 private OnClickListener closeListener = new OnClickListener() {
    @Override
    public void onClick(View v) {
        Intent jumpage = new Intent(Rent.this, MainActivity.class);
        startActivity(jumpage);
    }
};

就这么写

 private OnClickListener closeListener = new OnClickListener() {
    @Override
    public void onClick(View v) {
       this.finish();
    }
};

Answer 3

只需调用finish()关闭Rentactivity。

试试这个：

private OnClickListener closeListener = new OnClickListener() {
    @Override
    public void onClick(View v) {
        Intent jumpage = new Intent(Rent.this, MainActivity.class);
        startActivity(jumpage);

        finish();

    }
};

我的按钮 "close" 没有关闭而是隐藏了页面

My button "close" don't close but hide the page

java

android

button

return

forceclose