为什么每次输入都会出现 IllegalArgumentException？

Question

我需要创建一个程序来计算用户输入的测试分数的平均值。这实际上是我第二次接到任务要求制作这个程序。但是这次作业要我在用户输入小于 0 或大于 100 的测试分数时抛出 IllgalArgumentException。问题是无论测试分数是多少，即使测试分数在 0-100 之间，程序也会因 IllegalArgumentException 而崩溃.不确定我在做什么错任何想法这里的预期输出无一例外

预期输出

Enter number of test scores:5
Enter test score 1:70
Enter test score 2:65
Enter test score 3:94
Enter test score 4:55
Enter test score 5:90
74.8

和我的代码

public static void main(String[] args) throws IllegalArgumentException 
{
    Scanner input = new Scanner (System.in);
    int numTests = 0;
    int [] grade = new int [numTests];
    double average;
    double totalGrades = 0;

    System.out.print("Enter number of test scores:");
    numTests = input.nextInt();
    grade = new int[numTests];

    for (int index = 0; index < grade.length; index++)
    {
        System.out.print("Enter test score "  + (index + 1) + ":");
        grade[index] = input.nextInt();


            if(grade[index] < 0 || grade[index] > 100);
            {
                throw new IllegalArgumentException();

            }        
    }

    for (int i = 0; i < grade.length; i++)
    {
        totalGrades += grade[i];
    }

    average = totalGrades / grade.length;

    System.out.println(average);

}

private static class IllegalArgumentException extends Exception
{
    public IllegalArgumentException()
    {
        super("Test scores must have a value  less than  100 and greater than  0.");
    }

    public IllegalArgumentException(int value)
    {
        super("Invalid Test Score: " + value);
    }
}

Answer 1

if(grade[index] < 0 || grade[index] > 100);
{
  throw new IllegalArgumentException();
}

if 行末尾的 ; 表示 throw 无条件执行，因为它不在条件块中。

您的代码（实际上）与：

if(grade[index] < 0 || grade[index] > 100) { /* do nothing */ }
throw new IllegalArgumentException();

删除 ;.

为什么每次输入都会出现 IllegalArgumentException？

Why am i getting an IllegalArgumentException for every input?

java

illegalargumentexception