Attribute Error:'NoneType' object has no attribute 'parent'

Question

from urllib.request import urlopen
from bs4 import BeautifulSoup
html= urlopen("http://www.pythonscraping.com/pages/page3.html")
soup= BeautifulSoup(html.read())
print(soup.find("img",{"src":"../img/gifts/img1.jpg"
}).parent.previous_sibling.get_text())

上面的代码工作正常，但 below.It 的代码没有给出如上所述的属性错误。谁能告诉我原因吗？

from urllib.request import urlopen       
from bs4 import BeautifulSoup
html= urlopen("http://www.pythonscraping.com/pages/page3.html")
soup= BeautifulSoup(html.read())
price =soup.find("img",{"src=":"../img/gifts/img1.jpg"
}).parent.previous_sibling.get_text()
print(price)

谢谢！ :)

Answer 1

如果比较第一个和第二个版本，您会发现：

第一个： soup.find("img",{"src":"../img/gifts/img1.jpg"}).parent.previous_sibling.get_text()

• 注："src"

第二： soup.find("img","src=":"../img/gifts/img1.jpg"}).parent.previous_sibling.get_text()

• 注："src="

第二个代码returns Attribute Error:'NoneType' object has no attribute 'parent'因为在提供的汤中找不到src=="../img/gifts/img1.jpg"。

因此，如果您删除第二个版本中的 =，它应该可以工作。

---

顺便说一句，你应该明确你想使用哪个解析器，否则 bs4 将 return 以下警告：

UserWarning: No parser was explicitly specified, so I'm using the best available HTML parser for this system ("lxml"). This usually isn't a problem, but if you run this code on another system, or in a different virtual environment, it may use a different parser and behave differently.

To get rid of this warning, change code that looks like this:

BeautifulSoup([your markup])

to this:

BeautifulSoup([your markup], "lxml")

因此，如警告消息中所述，您只需将 soup = BeautifulSoup(html.read()) 更改为 soup = BeautifulSoup(html.read(), 'lxml')，例如。