如何在 doctrine2 queryBuilder 中实现 ON ( ... OR ...) mysql 查询
How to implement ON ( ... OR ...) mysql query in doctrine2 queryBuilder
我在 MYSQL 中有一个 SQL 查询:
例如
SELECT s.* FROM vplanning.cities as c1
INNER JOIN vplanning.cities as c2
ON (c1.id = c2.area_id)
INNER JOIN vplanning.storages as s
ON (s.city_id = c2.id OR s.city_id = c1.id)
WHERE c1.id = 109;
在学说上我可以这样写(来自我的工作代码):
$query = $em->getRepository('VplanningPageBundle:Storage')
->createQueryBuilder('s')
->innerJoin('s.city', 'c1')
->innerJoin('c1.area', 'c2')
->innerJoin('s.storagestype', 'st')
->where('c2.id = :cityID')
->andWhere('st.typename = :storagesTypeName')
->andWhere('s.active = :active')
->setParameters(array(
'cityID' => $cityID,
'storagesTypeName' => $storagesTypeName,
'active' => 1
))
->orderBy('s.adress')
->getQuery();
如你所见,我在
中显示了我的关系
->innerJoin('s.city', 'c1')
但我还需要像
这样的关系
->innerJoin('s.city', 'c2')
条件是:
ON (s.city_id = c2.id OR s.city_id = c1.id)
但是它抛出这个错误:
Error: 'c2' is already defined
c1
和c2
是同一个实体,有内在联系
试试这个:
$repository = $em->getRepository('VplanningPageBundle:Storage');
$qb = $repository->createQueryBuilder('storage');
//We can now use the expr()
$qb->join('storage.city', 'city', Join::WITH)
->join('city.area', 'area', Join::WITH, $qb->expr()->eq('area.id', ':cityID'))
->join('storage.storagestype', 'type', Join::WITH, $qb->expr()->eq('type.typename', ':storagesTypeName'))
->where('storage.active = :active')
->setParameters(array(
'cityID' => $cityID,
'storagesTypeName' => $storagesTypeName,
'active' => 1
))
->orderBy('storage.adress');
$query = $qb->getQuery();
像这样试试
$qb = $this->getRepository('VplanningPageBundle:City')->createQueryBuilder('c');
$qb->leftJoin('c.area', 'a')
->join('c.storage', 's', Join::ON, $qb->expr()->orX($qb->expr()->eq('c.id', 's.id'), $qb->expr()->eq('a.id', 's.id')))
->innerJoin('s.storagestype', 'st')
->where('c.id = :cityID')
->andWhere('st.typename = :storagesTypeName')
->andWhere('s.active = :active')
->setParameters(array(
'cityID' => $cityID,
'storagesTypeName' => $storagesTypeName,
'active' => 1,
))
->orderBy('s.adress')
->getQuery()
;
问题的解决对我来说很难,我必须研究一下:)
这是某个论坛版块对我的问题的回答:
$qb = $em->getRepository('VplanningPageBundle:Storage')->createQueryBuilder('storage');
$query = $qb->join('storage.city', 'city1', Join::WITH)
->leftJoin('city1.area', 'area', Join::WITH, $qb->expr()->eq('area.id', ':cityID'))
->leftJoin('storage.city', 'city2', Join::WITH, $qb->expr()->eq('city2.id', ':cityID'))
->join('storage.storagestype', 'type', Join::WITH, $qb->expr()->eq('type.typename', ':storagesTypeName'))
->where('storage.active = :active')
->andWhere($qb->expr()->orX($qb->expr()->isNotNull('city2'), $qb->expr()->isNotNull('area')))
->setParameters(array(
'cityID' => $cityID,
'storagesTypeName' => $storagesTypeName,
'active' => 1
))
->orderBy('storage.adress')
->getQuery();
我在 MYSQL 中有一个 SQL 查询: 例如
SELECT s.* FROM vplanning.cities as c1
INNER JOIN vplanning.cities as c2
ON (c1.id = c2.area_id)
INNER JOIN vplanning.storages as s
ON (s.city_id = c2.id OR s.city_id = c1.id)
WHERE c1.id = 109;
在学说上我可以这样写(来自我的工作代码):
$query = $em->getRepository('VplanningPageBundle:Storage')
->createQueryBuilder('s')
->innerJoin('s.city', 'c1')
->innerJoin('c1.area', 'c2')
->innerJoin('s.storagestype', 'st')
->where('c2.id = :cityID')
->andWhere('st.typename = :storagesTypeName')
->andWhere('s.active = :active')
->setParameters(array(
'cityID' => $cityID,
'storagesTypeName' => $storagesTypeName,
'active' => 1
))
->orderBy('s.adress')
->getQuery();
如你所见,我在
中显示了我的关系->innerJoin('s.city', 'c1')
但我还需要像
这样的关系->innerJoin('s.city', 'c2')
条件是:
ON (s.city_id = c2.id OR s.city_id = c1.id)
但是它抛出这个错误:
Error: 'c2' is already defined
c1
和c2
是同一个实体,有内在联系
试试这个:
$repository = $em->getRepository('VplanningPageBundle:Storage');
$qb = $repository->createQueryBuilder('storage');
//We can now use the expr()
$qb->join('storage.city', 'city', Join::WITH)
->join('city.area', 'area', Join::WITH, $qb->expr()->eq('area.id', ':cityID'))
->join('storage.storagestype', 'type', Join::WITH, $qb->expr()->eq('type.typename', ':storagesTypeName'))
->where('storage.active = :active')
->setParameters(array(
'cityID' => $cityID,
'storagesTypeName' => $storagesTypeName,
'active' => 1
))
->orderBy('storage.adress');
$query = $qb->getQuery();
像这样试试
$qb = $this->getRepository('VplanningPageBundle:City')->createQueryBuilder('c');
$qb->leftJoin('c.area', 'a')
->join('c.storage', 's', Join::ON, $qb->expr()->orX($qb->expr()->eq('c.id', 's.id'), $qb->expr()->eq('a.id', 's.id')))
->innerJoin('s.storagestype', 'st')
->where('c.id = :cityID')
->andWhere('st.typename = :storagesTypeName')
->andWhere('s.active = :active')
->setParameters(array(
'cityID' => $cityID,
'storagesTypeName' => $storagesTypeName,
'active' => 1,
))
->orderBy('s.adress')
->getQuery()
;
问题的解决对我来说很难,我必须研究一下:)
这是某个论坛版块对我的问题的回答:
$qb = $em->getRepository('VplanningPageBundle:Storage')->createQueryBuilder('storage');
$query = $qb->join('storage.city', 'city1', Join::WITH)
->leftJoin('city1.area', 'area', Join::WITH, $qb->expr()->eq('area.id', ':cityID'))
->leftJoin('storage.city', 'city2', Join::WITH, $qb->expr()->eq('city2.id', ':cityID'))
->join('storage.storagestype', 'type', Join::WITH, $qb->expr()->eq('type.typename', ':storagesTypeName'))
->where('storage.active = :active')
->andWhere($qb->expr()->orX($qb->expr()->isNotNull('city2'), $qb->expr()->isNotNull('area')))
->setParameters(array(
'cityID' => $cityID,
'storagesTypeName' => $storagesTypeName,
'active' => 1
))
->orderBy('storage.adress')
->getQuery();