UIActivityViewController 为 WhatsApp 或 Facebook 选择了不同的文本

UIActivityViewController chose different text for WhatsApp or Facebook

我在 activity 项中有文本,但现在它在 WhatsApp 或 Facebook 上共享,此方法为每个应用程序共享相同的文本。 是否可以为每个应用共享不同的文本?

- (void)share {
    NSString *text = @"share test";

    NSArray * activityItems = @[[NSString stringWithFormat:@"%@", text], [NSURL URLWithString:@"http://www.test.co"]];
    NSArray * applicationActivities = nil;
    NSArray * excludeActivities = @[UIActivityTypeAssignToContact, UIActivityTypeCopyToPasteboard, UIActivityTypePostToWeibo, UIActivityTypePrint, UIActivityTypeMessage];

    UIActivityViewController * activityController = [[UIActivityViewController alloc] initWithActivityItems:activityItems applicationActivities:applicationActivities];
    activityController.excludedActivityTypes = excludeActivities;

    [self presentViewController:activityController animated:YES completion:nil];

    [activityController setCompletionWithItemsHandler:^(NSString *activityType, BOOL completed, NSArray *returnedItems, NSError *activityError) {
        NSLog(@"The setCompletionWithItemsHandler completed = %i", completed);

        if (completed) {
            NSLog(@"The selected activity was %@", activityType);

            if ( [activityType isEqualToString:UIActivityTypeMail]) {
                NSLog(@"Mail sended");
            } else if ( [activityType isEqualToString:UIActivityTypePostToTwitter]) {
                NSLog(@"Post on twitter, ok!");
            } else if ( [activityType isEqualToString:UIActivityTypePostToFacebook]) {
                NSLog(@"Post on facebook, ok!");
            } else if ( [activityType isEqualToString:UIActivityTypeMessage]) {
                NSLog(@"SMS sended!");
            }
        }
    }];
}

简答:否

但是你可以使用open App with URL的方法,然后给那个App传递一个参数。 使用该方法时,您必须使用自定义 UI 而不能使用 UIActivityViewController。 (据我所知)

因此,如果您想要多个按钮,则有可能: "Share with WhatsApp" "Share with Facebook" 等等

简答:是的!

实际上有一种方法可以 return 选择多个应用程序后的不同内容。

您将必须创建两个 UIActivityItemSource,一个将 return 一个 UIImage,另一个将 return 一个 NSObject。这是为了 "fool" 您将共享这些对象的系统,但是在用户选择了一个应用程序之后,我们实际上可以 return 其他东西,比如 URL.

class SocialActivityItem: NSObject, UIActivityItemSource {
    var img: UIImage?
    var url: URL?

    convenience init(img: UIImage, url: URL) {
        self.init()
        self.img = img
        self.url = url
    }

    // This will be called BEFORE showing the user the apps to share (first step)
    func activityViewControllerPlaceholderItem(_ activityViewController: UIActivityViewController) -> Any {
        return img!
    }

    // This will be called AFTER the user has selected an app to share (second step)
    func activityViewController(_ activityViewController: UIActivityViewController, itemForActivityType activityType: UIActivityType?) -> Any? {
        //Instagram
        if activityType?.rawValue == "com.burbn.instagram.shareextension" {
            return img!
        } else {
            return url
        }
    }
}

class TextActivityItem: NSObject, UIActivityItemSource {
    var textToShare: String?

    convenience init(textToShare: String) {
        self.init()
        self.textToShare = textToShare
    }

    // This will be called BEFORE showing the user the apps to share (first step)
    func activityViewControllerPlaceholderItem(_ activityViewController: UIActivityViewController) -> Any {
        return NSObject()
    }

    // This will be called AFTER the user has selected an app to share (second step)
    func activityViewController(_ activityViewController: UIActivityViewController, itemForActivityType activityType: UIActivityType?) -> Any? {
      var text = ""
      if activityType?.rawValue == "net.whatsapp.WhatsApp.ShareExtension" {
          text = "Sharing on Whatsapp"
      }

      if activityType == UIActivityType.postToFacebook {
          text = "Sharing on Facebook"
      }
      return text.isEmpty ? textToShare : text
    }
}

然后,您只需要设置好一切:

let url = URL(string: "www.google.com")!
let socialProvider = SocialActivityItem(img: img, url: url)
let textProvider = TextActivityItem(textToShare: "Sharing on social media!")
let activityViewController = UIActivityViewController(activityItems: [socialProvider, textProvider], applicationActivities: nil)