在 rails 应用程序上实施 friendly_id 后，旧网址仍然有效。我怎样才能阻止他们并重定向到 404？

Question

我在我的 rails 应用程序上实现了 friendly_id。之前单击 link 时，url 曾经如下所示：

https://example.com/search?category_id=228

执行 friendly_id 后，当 link 被点击时，它开始给出 url 如下：

https://example.com/search?category_id=construction-and-heavy-equipment

我在平台上实现了一个404方法。当给出无效的 urls 时，它会重定向到 404 错误页面。它适用于无效的 urls.

但是现在当我测试给旧的url即https://example.com/search?category_id=228时它仍然有效。我该如何阻止它？

控制器

  def search_equipments
    begin
      if (params.keys & ['category_id', 'sub_category', 'manufacturer', 'country', 'state', 'keyword']).present?
        if params[:category_id].present?
          @category = Category.active.find params[:category_id]
        else
          @category = Category.active.find params[:sub_category] if params[:sub_category].present?
        end
        @root_categories = Category.active.roots
        @sub_categories = @category.children.active if params[:category_id].present?
        @sub_categories ||= {}
        @countries = Country.active.all
        @manufacturers = Manufacturer.active.all
        @states = State.active.where("country_id = ?", params[:country]) if params[:country].present?
        @states ||= {} 
        unless params[:category_id].present? && params[:sub_category].present?
          params[:category_id] = @category.id if params[:category_id].present?
          params[:sub_category] = @category.id if params[:sub_category].present?
        end   
        @equipments = Equipment.active.filter(params.slice(:manufacturer, :country, :state, :category_id, :sub_category, :keyword)).order("#{sort_column} #{sort_direction}, created_at desc").page(params[:page]).per(per_page_items)               
      else
        redirect_to root_path
      end
    rescue Exception => e
      redirect_to root_path, :notice => "Something went wrong!"
    end

  end

担忧

module Filterable
  extend ActiveSupport::Concern

  module ClassMethods
    def filter(filtering_params)
      results = self.where(nil)
      filtering_params.each do |key, value|
        results = results.public_send(key, value) if value.present?
      end
      results
    end
  end
end

Answer 1

根据friendly_id源代码，你应该使用find_by_friendly_id。因为 find 方法首先通过 slug 查询，然后回退到常规 find 方法。

# If the id is "unfriendly", it will call the original find method.
# If the id is a numeric string like '123' it will first look for a friendly
# id matching '123' and then fall back to looking for a record with the
# numeric id '123'.
#
# Since FriendlyId 5.0, if the id is a numeric string like '123-foo' it
# will *only* search by friendly id and not fall back to the regular find
# method.
#
# If you want to search only by the friendly id, use {#find_by_friendly_id}.

更改代码

@category = Category.active.find params[:category_id]

至此

@category = Category.active.friendly.find_by_friendly_id params[:category_id]

并检查 https://github.com/norman/friendly_id/issues/648#issuecomment-75172624，这是另一个解决方案，但更复杂。

Answer 2

您可以通过两种方式做到这一点：

您可以发送 slug.

id

如果您在请求中找到数字 id，其他方法是在 controller 中设置一些 redirect 代码。

在 rails 应用程序上实施 friendly_id 后，旧网址仍然有效。我怎样才能阻止他们并重定向到 404？

Old urls are still working after implementing friendly_id on rails app. How can I stop them and redirect to 404?

ruby-on-rails

friendly-id