锯齿状数组的输入值

Question

好的，我正在尝试制作一个简单的程序，读取给定日期售出的比萨饼数量，然后让用户输入当天售出的比萨饼类型（为此我需要使用 Split () 与用户输入).

我在填充锯齿状数组的列时遇到问题。

现在，我只需要为售出 1 个比萨饼而工作，但除此之外，它不会考虑我的用户输入的当天售出的比萨饼类型（列值）。它不会将用户输入作为单独的项目读取，所以一旦我输入，它就会转到下一行，就像它在等待数据而不是继续前进一样。（由于我对此进行了一天的测试，一旦读入用户输入，它就会结束程序）。

我不太确定我的问题出在我的循环中放入我的列值，但我认为它与读取用户输入并将其放置在锯齿状数组的列中有关。任何帮助都会很棒。

static void Main(string[] args)
    {
        Greeting();
        string[][] pizza = new string[7][];
        GetPizzas(pizza);

    }

    static void Greeting()
    {
        Write("Welcome to Z's Pizza Report!");
    }

    static void GetPizzas(string[][] array)
    {
        int numOfPizza;
        string day;
        for (int r = 0; r < array.Length; r++)
        {
            if (r == 0)
            {
                day = "Monday";
                Write("How many total pizzas were there for {0}? ", day);
                numOfPizza = int.Parse(ReadLine());
                while (numOfPizza < 0)
                {
                    Write("Number cannot be negative. Try Again: ");
                    numOfPizza = int.Parse(ReadLine());
                }

                array[r] = new string[numOfPizza];
                Write("Enter all the pizzas for {0}, seperated by spaces: ", day);

                for (int c = 0; c < array[r].Length; c++)
                {
                    string total = ReadLine();
                    array[c] = total.Split(' ');
                    while (array[r] != array[c])
                    {
                        Write("Input does not match number needed. Try Again: ");
                        total = ReadLine();
                        array[c] = total.Split(' ');
                    }
                }
            }
            else if (r == 1)
            {
                day = "Tuesday";
            }
            else if (r == 2)
            {
                day = "Wednesday";
            }
            else if (r == 3)
            {
                day = "Thursday";
            }
            else if (r == 4)
            {
                day = "Friday";
            }
            else if (r == 5)
            {
                day = "Saturday";
            }
            else
            {
                day = "Sunday";
            }

        }
    }

Answer 1

代码对我来说似乎过于复杂，但这样的事情有帮助吗？哦，请注意我正在使用内置的 DayOfWeek 枚举来解析当天的友好名称。这和你的区别在于 Sunday 是第 0 天。

这行代码将整数转换为枚举，然后得到字符串值：

var dayOfWeek = ((DayOfWeek)i).ToString();

我还添加了一个辅助函数来从用户那里获取一个整数。它接收一个提示字符串、一个错误字符串、一个可选的最小值和一个可选的最大值，然后它会提示用户输入一个整数并且不会 return 直到他们输入有效值：

static int GetIntFromUser(string prompt, string error, 
    int minValue = int.MinValue, int maxValue = int.MaxValue)
{
    int result;

    if (!string.IsNullOrEmpty(prompt)) Console.Write(prompt);

    while (!int.TryParse(Console.ReadLine(), out result) 
           || result < minValue || result > maxValue)
    {
        if (!string.IsNullOrEmpty(error)) Console.Write(error);
    }

    return result;
}

其余代码如下所示：

static void Main(string[] args)
{
    var pizzasSold = new string[7][];

    GetPizzas(pizzasSold);

    for (int i = 0; i < pizzasSold.Length; i++)
    {
        var dayOfWeek = ((DayOfWeek)i).ToString();
        Console.WriteLine("You sold {0} pizzas on {1}: {2}", 
            pizzasSold[i].Length, dayOfWeek, string.Join(", ", pizzasSold[i]));
    }

    Console.Write("\nDone!\nPress any key to exit...");
    Console.ReadKey();
}

static void GetPizzas(string[][] array)
{
    for (int r = 0; r < array.Length; r++)
    {
        var dayOfWeek = ((DayOfWeek)r).ToString();

        var numPizzasSold =
                GetIntFromUser($"How many total pizzas were there for {dayOfWeek}? ",
                "Number cannot be negative. Try Again: ", 0);

        Console.Write($"Enter all the pizzas for {dayOfWeek}, seperated by spaces: ");
        var pizzasSold = Console.ReadLine().Split(new[] { ' ' }, 
            StringSplitOptions.RemoveEmptyEntries);

        while (pizzasSold.Length != numPizzasSold)
        {
            Console.Write($"Input does not match number needed. Try Again: ");
            pizzasSold = Console.ReadLine().Split(new[] { ' ' }, 
                StringSplitOptions.RemoveEmptyEntries);
        }

        array[r] = pizzasSold;
    }
}

Answer 2

using System;

namespace ConsoleApp12
{
    class Program
    {
        static void Main(string[] args)
        {
            int[][] n = new int[3][];
            int i;
            n[0] = new int[4];
            n[1] = new int[3];
            n[2] = new int[2];
            // n[1] = new int[] { 1, 2, 3 };
            // Console.WriteLine("enter the rollno");
            for (i = 0; i < 4; i++)
            {

                n[0][i] = Convert.ToInt32(Console.ReadLine());


            }
            for (i = 0; i < 3; i++)
            {

                n[1][i] = Convert.ToInt32(Console.ReadLine());


            }
            for (i = 0; i < 2; i++)
            {

                n[2][i] = Convert.ToInt32(Console.ReadLine());


            }


            //   for (i = 0; i < 3; i++)
            // {
            //   n[i][j] = Convert.ToInt32(Console.ReadLine());
            //}

            for (i = 0; i <4; i++)
            
                              {
                    Console.Write(n[0][i] + " ");
                }
            Console.WriteLine();
           for (i = 0; i < 3; i++)
            
                    {
                        Console.Write(n[1][i] + " ");
                    }

                

            }
    }
}

锯齿状数组的输入值

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