Symfony 如何测试 AJAX 请求
Symfony how to test an AJAX request
在我的项目中,我有一个发送 AJAX 请求的表格:
$.ajax({
url: '/bio_control/sample',
type: 'POST',
dataType: 'json',
data: {sample_number: $(input_field).val()},
});
激活以下控制器方法:
/**
* @Route("/bio_control/sample", name="get_bio_control_sample")
*/
public function getBioControlSampleAction(Request $request)
{
$sample_number = $request->request->get('sample_number');
/**
* Additional logic not shown for brevity.
*/
$user_id = $user->getId();
$response = array("code" => 100, "success" => true, "sample_number" => $sample_number, "sample_data" => $sample[0], "new_user" => false, "user_id" => $user_id);
return new JsonResponse($response);
}
我希望能够单独测试此请求,但我不确定如何编写请求对象。
到目前为止我的第一次尝试:
public function testGetBioControlSample()
{
$helper = $this->helper;
$client = $this->makeClient();
$crawler = $client->request('POST', "/bio_control/sample", array(), array('sample_number' => 67655), array(
'CONTENT_TYPE' => 'application/json',
'HTTP_X-Requested-With' => 'XMLHttpRequest'
));
$this->assertStatusCode(200, $client);
}
失败,因为它似乎正在提交表单(我收到一个与表单字段相关的错误,与 AJAX 请求为空完全无关)。
任何人都可以演示如何正确编写这样的测试吗?
这个URL需要身份验证吗?
我喜欢使用 LiipFunctionalTestBundle 进行功能测试,它们通常如下所示:
<?php
declare(strict_types=1);
namespace Tests\Your\Namespace;
use Liip\FunctionalTestBundle\Test\WebTestCase;
class PostResourceActionTest extends WebTestCase
{
public function testShouldReturnResponseWithOkStatusCode(): void
{
$credentials = [
'username' => 'user',
'password' => 'pass'
];
$client = $this->makeClient($credentials);
$payload = ['foo' => 'bar'];
$client->request(
'POST',
'/the/url/',
$payload,
[],
['HTTP_Content-Type' => 'application/json']
);
$this->assertStatusCode(200, $client);
}
}
也许您遇到的错误是要求身份验证的登录表单?
我用来解决这个问题的确切语法是:
public function testGetBioControlSample()
{
$helper = $this->helper;
$client = $this->makeClient();
$crawler = $client->request(
'POST',
"/bio_control/sample",
array('sample_number' => 67655),
array(),
array('HTTP_Content-Type' => 'application/json')
);
$JSON_response = json_decode($client->getResponse()->getContent(), true);
$this->assertStatusCode(200, $client);
$this->assertNotEmpty($JSON_response);
$this->assertEquals($JSON_response["code"], 100);
$this->assertEquals($JSON_response["success"], true);
$this->assertEquals($JSON_response["sample_number"], 67655);
}
我相信我不需要:'HTTP_X-Requested-With' => 'XMLHttpRequest'
在最后的数组参数中。
此外,我 array('sample_number' => 67655)
的参数有误。
Symfony 4.1 has a new way of testing AJAX requests:
// Before
$crawler = $client->request('GET', '/some/path', [], [], [
'HTTP_X-Requested-With' => 'XMLHttpRequest',
]);
// After
$crawler = $client->xmlHttpRequest('GET', '/some/path');
在我的项目中,我有一个发送 AJAX 请求的表格:
$.ajax({
url: '/bio_control/sample',
type: 'POST',
dataType: 'json',
data: {sample_number: $(input_field).val()},
});
激活以下控制器方法:
/**
* @Route("/bio_control/sample", name="get_bio_control_sample")
*/
public function getBioControlSampleAction(Request $request)
{
$sample_number = $request->request->get('sample_number');
/**
* Additional logic not shown for brevity.
*/
$user_id = $user->getId();
$response = array("code" => 100, "success" => true, "sample_number" => $sample_number, "sample_data" => $sample[0], "new_user" => false, "user_id" => $user_id);
return new JsonResponse($response);
}
我希望能够单独测试此请求,但我不确定如何编写请求对象。
到目前为止我的第一次尝试:
public function testGetBioControlSample()
{
$helper = $this->helper;
$client = $this->makeClient();
$crawler = $client->request('POST', "/bio_control/sample", array(), array('sample_number' => 67655), array(
'CONTENT_TYPE' => 'application/json',
'HTTP_X-Requested-With' => 'XMLHttpRequest'
));
$this->assertStatusCode(200, $client);
}
失败,因为它似乎正在提交表单(我收到一个与表单字段相关的错误,与 AJAX 请求为空完全无关)。
任何人都可以演示如何正确编写这样的测试吗?
这个URL需要身份验证吗?
我喜欢使用 LiipFunctionalTestBundle 进行功能测试,它们通常如下所示:
<?php
declare(strict_types=1);
namespace Tests\Your\Namespace;
use Liip\FunctionalTestBundle\Test\WebTestCase;
class PostResourceActionTest extends WebTestCase
{
public function testShouldReturnResponseWithOkStatusCode(): void
{
$credentials = [
'username' => 'user',
'password' => 'pass'
];
$client = $this->makeClient($credentials);
$payload = ['foo' => 'bar'];
$client->request(
'POST',
'/the/url/',
$payload,
[],
['HTTP_Content-Type' => 'application/json']
);
$this->assertStatusCode(200, $client);
}
}
也许您遇到的错误是要求身份验证的登录表单?
我用来解决这个问题的确切语法是:
public function testGetBioControlSample()
{
$helper = $this->helper;
$client = $this->makeClient();
$crawler = $client->request(
'POST',
"/bio_control/sample",
array('sample_number' => 67655),
array(),
array('HTTP_Content-Type' => 'application/json')
);
$JSON_response = json_decode($client->getResponse()->getContent(), true);
$this->assertStatusCode(200, $client);
$this->assertNotEmpty($JSON_response);
$this->assertEquals($JSON_response["code"], 100);
$this->assertEquals($JSON_response["success"], true);
$this->assertEquals($JSON_response["sample_number"], 67655);
}
我相信我不需要:'HTTP_X-Requested-With' => 'XMLHttpRequest'
在最后的数组参数中。
此外,我 array('sample_number' => 67655)
的参数有误。
Symfony 4.1 has a new way of testing AJAX requests:
// Before
$crawler = $client->request('GET', '/some/path', [], [], [
'HTTP_X-Requested-With' => 'XMLHttpRequest',
]);
// After
$crawler = $client->xmlHttpRequest('GET', '/some/path');