Java PHP 中的 Sha1

Question

如何在 PHP 中得到这个 Java SHA1 结果？

    // Generating the Signature - Java
// import java.security.MessageDigest;
// import org.apache.commons.codec.binary.Base64;

String userId; 
String applicationKey; // E.g. "196087a1-e815-4bc4-8984-60d8d8a43f1d";
String applicationSecret; // E.g. "oYdgGRXoxEuJhGDY2KQ/HQ==";
long sequence; // fetch and increment last used sequence

String toSign = userId + applicationKey + sequence + applicationSecret;

MessageDigest messageDigest = MessageDigest.getInstance("SHA-1");
byte[] hash = messageDigest.digest(toSign.getBytes("UTF-8"));

String signature = Base64.encodeBase64String(hash).trim();

我需要 PHP 上的 UTF-8 Sha1，谢谢

这些代码输出的结果不同于 java utf-8 sha-1:

1:

$toSign_base64 = trim(base64_encode($toSign));
$toSign_digest = trim(hash_hmac('sha1', base64_decode($toSign_base64), "", true));
$signature = trim(base64_encode($toSign_digest));

2:

$signature = trim(sha1($toSign));

3:

$signature = trim(base64_encode(sha1($toSign)));

结果：

"raw": "849165ca-7af7-4951-6969-e19fc9f50b66",
"java_utf8_sha1": "1kBtMaSGLLiUfoSh9qJaxQGZTiQ=",
"code_1": "07PGV/+gMgCylXyA2qPJ92y1eSo=",
"code_2": "d6406d31a4862cb8947e84a1f6a25ac501994e24",
"code_3": "ZDY0MDZkMzFhNDg2MmNiODk0N2U4NGExZjZhMjVhYzUwMTk5NGUyNA=="

Answer 1

我 90% 确定 php 函数 sha1();使用utf8编码，输出为raw，然后base64_encode它，所以

<?php  base64_encode( sha1("849165ca-7af7-4951-6969-e19fc9f50b66", true) ); ?>

看看它给你的是不是和java一样（我不知道java，只知道php）

Java PHP 中的 Sha1

Java Sha1 in PHP

java

php

encryption

sha1

sinch