如何获取数组中不包含具有特定值的对象的文档

Question

比如我有两个文件：

{
  communication: "some data 1"
  users: [
    {
      name: 'Peter',
      role: 'admin'
      gender: 'male'
    },
    {
      name: 'John',
      role: 'guest'
      gender: 'male'
    }
  ]
}


{
  communication: "some data 2"
  users: [
    {
      name: 'Kollins',
      role: 'admin'
      gender: 'male'
    },
    {
      name: 'Steve',
      role: 'moderator'
      gender: 'male'
    }
  ]
}

最后，我必须获取 users 数组中没有 user 和 role: 'guest' 的文档。基于两个文档的示例，我必须获得第二个。伪代码是这样的： select * from bucket where users.role = 'guest' is missing

Answer 1

您需要使用 ARRAY and check if there is a user with NOT EXISTS

映射用户数组

SELECT * FROM bucket WHERE NOT EXISTS ARRAY users FOR user IN users 
WHEN user.role='guest' END

如何获取数组中不包含具有特定值的对象的文档

How to obtain documents which don't contain object with specific value inside an array

couchbase

nickel